错误 TS2345：“OperatorFunction<User, void>”类型的参数不可分配给“OperatorFunction<Object, void>”类型的参数

Question

我是 Angular 的新手。

我该如何解决这个问题？

我已经安装了 Angular CLI: 11.0.7 和 Node: 12.18.4

错误：

<块引用>

错误：src/app/_services/account.service.ts:19:7 - 错误 TS2345： “OperatorFunction”类型的参数不可分配给 'OperatorFunction' 类型的参数。 “对象”类型可分配给很少的其他类型。您是想改用“any”类型吗？ “对象”类型缺少“用户”类型中的以下属性：用户名、令牌

 19       map((response: User) => {
          ~~~~~~~~~~~~~~~~~~~~~~~~~
 20         const user = response;
    ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
...
 24         }
    ~~~~~~~~~
 25       })
    ~~~~~~~~

account.service.ts

import { HttpClient } from '@angular/common/http';
import { Injectable } from '@angular/core';
import {map} from 'rxjs/operators';
import { User } from '../_models/user';
import { ReplaySubject } from 'rxjs';


export class AccountService {
  baseUrl = 'https://localhost:5001/api/';
  private currentUserSource = new ReplaySubject<User>(1);
  currentUser$ = this.currentUserSource.asObservable();

  constructor(private http: HttpClient) { }

  login(model: any) {
    return this.http.post(this.baseUrl + 'account/login', model).pipe(
      map((response: User) => {
        const user = response;
        if (user) {
          localStorage.setItem('user', JSON.stringify(user));
          this.currentUserSource.next(user);
        }
      })
    )
  }
}

user.ts

export interface User{
    username: string;
    token: string;
}

Answer 1

你需要转换 http.post 返回

  login(model: any) {
    //-------------- here ⇊⇊ ------
    return this.http.post<User>(this.baseUrl + 'account/login', model).pipe(
      map((user : User) => {
        if (user) {
          localStorage.setItem('user', JSON.stringify(user));
          this.currentUserSource.next(user);
        }
      })
    )
  }

Answer 2

http.post 可以被类型转换为 User 或任何

也试试

login(model: any){
    return this.http.post(this.baseUrl + 'account/login', model).pipe(
      map((response: User)=>{
        const user = response as User;
        if(user){
          localStorage.setItem('user', JSON.stringify(user));
          this.currentUserSource.next(user);
        }
      })
    )
  }

Answer 3

Typescript: Type 'string | undefined' is not assignable to type 'string'

"strict": true >>>> "strict": false