我有TreeListViewItem
的样式......实际上只是“树结构”中的ListViewItem
。 DataContext
的{{1}}设置为我的视图模型,其ListViewItem
属性绑定到项IsSelected
。我进行了更改,以便在选择项目时,以不同方式设置项目样式,并将viewmodel上的属性设置为“true”。这很好用,但是当我为IsSelected
添加了一个触发器时,viewmodel属性不再被设置。项目的样式仍然会更改,但我还需要在viewmodel上更改属性。任何帮助都会很棒。
XAML:
IsKeyboardFocusWithin
ViewModel代码:
<Style TargetType="{x:Type zcorectl:ZynTreeListViewItem}">
<Setter Property="KeyboardNavigation.TabNavigation" Value="Continue"/>
<Setter Property="IsExpanded" Value="{Binding Path=IsExpanded, Mode=TwoWay}"/>
<Setter Property="IsSelected" Value="{Binding Path=IsSelected, UpdateSourceTrigger=PropertyChanged}"/>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type zcorectl:ZynTreeListViewItem}">
<StackPanel>
<Border x:Name="Bd" Background="{TemplateBinding Background}" BorderBrush="{TemplateBinding BorderBrush}" BorderThickness="{TemplateBinding BorderThickness}" Padding="{TemplateBinding Padding}">
<GridViewRowPresenter x:Name="PART_Header" Content="{TemplateBinding Header}" Columns="{StaticResource columns}" />
</Border>
<ItemsPresenter x:Name="ItemsHost"/>
</StackPanel>
<ControlTemplate.Triggers>
<Trigger Property="IsExpanded" Value="false">
<Setter TargetName="ItemsHost" Property="Visibility" Value="Collapsed"/>
</Trigger>
<MultiTrigger>
<MultiTrigger.Conditions>
<Condition Property="HasHeader" Value="false"/>
<Condition Property="Width" Value="Auto"/>
</MultiTrigger.Conditions>
<Setter TargetName="PART_Header" Property="MinWidth" Value="75"/>
</MultiTrigger>
<MultiTrigger>
<MultiTrigger.Conditions>
<Condition Property="HasHeader" Value="false"/>
<Condition Property="Height" Value="Auto"/>
</MultiTrigger.Conditions>
<Setter TargetName="PART_Header" Property="MinHeight" Value="19"/>
</MultiTrigger>
<Trigger Property="IsKeyboardFocusWithin" Value="True">
<Setter Property="IsSelected" Value="True"/>
</Trigger>
<Trigger Property="IsSelected" Value="true">
<Setter TargetName="Bd" Property="BorderBrush" Value="{DynamicResource {x:Static SystemColors.HighlightBrushKey}}"/>
<Setter TargetName="Bd" Property="BorderThickness" Value="0,2"/>
<Setter TargetName="Bd" Property="Height" Value="45"/>
<Setter Property="Foreground" Value="{DynamicResource {x:Static SystemColors.HighlightTextBrushKey}}"/>
</Trigger>
<MultiTrigger>
<MultiTrigger.Conditions>
<Condition Property="IsSelected" Value="true"/>
<Condition Property="IsSelectionActive" Value="false"/>
</MultiTrigger.Conditions>
<Setter TargetName="Bd" Property="BorderBrush" Value="{DynamicResource {x:Static SystemColors.ControlBrushKey}}"/>
<Setter TargetName="Bd" Property="BorderThickness" Value="0,2"/>
<Setter TargetName="Bd" Property="Height" Value="45"/>
<Setter Property="Foreground" Value="{DynamicResource {x:Static SystemColors.ControlTextBrushKey}}"/>
</MultiTrigger>
<Trigger Property="IsEnabled" Value="false">
<Setter Property="Foreground" Value="{DynamicResource {x:Static SystemColors.GrayTextBrushKey}}"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
答案 0 :(得分:0)
为什么不在ViewModel中创建一个KeyboardFocus属性并将逻辑放在那里?
private bool _isKeyboardFocusSet = false;
public bool IsKeyboardFocusSet
{
get { return _isKeyboardFocusSet; }
set
{
if (_isKeyboardFocusSet!= value)
{
_isKeyboardFocusSet = value;
OnPropertyChanged("isKeyboardFocusSet");
}
if (_isSelected != true)
{
_isSelected = _isKeyboardFocusSet;
OnPropertyChanged("IsSelected");
}
}
}