如何将base64编码的图像发送到FastAPI后端

时间:2020-11-11 15:06:04

标签: javascript fastapi

我正在使用thisthat answer中的代码将base64编码的图像发送到python FastAPI后端。客户端看起来像这样:

function toDataURL(src, callback, outputFormat) {
            var img = new Image();
            img.crossOrigin = 'Anonymous';
            img.onload = function() {
                var canvas = document.createElement('CANVAS');
                var ctx = canvas.getContext('2d');
                var dataURL;
                canvas.height = this.naturalHeight;
                canvas.width = this.naturalWidth;
                ctx.drawImage(this, 0, 0);
                dataURL = canvas.toDataURL(outputFormat);
                callback(dataURL);
            };
            img.src = src;
            if (img.complete || img.complete === undefined) {
                img.src = "data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///ywAAAAAAQABAAACAUwAOw==";
                img.src = src;
            }
        }

        function makeBlob(dataURL) {
            var BASE64_MARKER = ';base64,';
            if (dataURL.indexOf(BASE64_MARKER) == -1) {
                var parts = dataURL.split(',');
                var contentType = parts[0].split(':')[1];
                var raw = decodeURIComponent(parts[1]);
                return new Blob([raw], { type: contentType });
            }
            var parts = dataURL.split(BASE64_MARKER);
            var contentType = parts[0].split(':')[1];
            var raw = window.atob(parts[1]);
            var rawLength = raw.length;

            var uInt8Array = new Uint8Array(rawLength);

            for (var i = 0; i < rawLength; ++i) {
                uInt8Array[i] = raw.charCodeAt(i);
            }

            return new Blob([uInt8Array], { type: contentType });
        }

        ...

        toDataURL(
            images[0], // images is an array of paths to images
            function(dataUrl) {
                console.log('RESULT:', dataUrl);

                $.ajax({
                    url: "http://0.0.0.0:8000/check/",
                    type: 'POST',
                    processData: false,
                    contentType: 'application/octet-stream',
                    data: makeBlob(dataUrl)
                }).done(function(data) {console.log("success");}).fail(function() {console.log("error");});
            }
        );

服务器端如下:

@app.post("/check")
async def check(file: bytes = File(...)) -> Any:  
    // do something here

我只显示端点的签名,因为现在无论如何都没有发生任何事情。

如下所示,这是后端的输出:

172.17.0.1:36464-“ OPTIONS / check / HTTP / 1.1” 200

172.17.0.1:36464-“ POST / check / HTTP / 1.1” 307

172.17.0.1:36464-“选项/检查HTTP / 1.1” 200

172.17.0.1:36464-“ POST / check HTTP / 1.1” 422

简而言之,我一直收到422错误代码,这意味着我发送的内容与端点期望的内容不匹配,但是即使经过一番阅读,我仍然不清楚问题到底出在哪里。任何帮助将是最欢迎的!

0 个答案:

没有答案