Question

我想实施一个长期运行的后台任务，可以将进度报告给其他Actor。我已经做到了。但我也希望能够再次取消长期运行的后台任务。

到目前为止，我是这样的：

use actix::prelude::*;

struct Worker {}

impl Actor for Worker {
    type Context = SyncContext<Self>;
}

struct Manager {
    worker: Addr<Worker>,
}

impl Actor for Manager {
    type Context = Context<Self>;
}

impl Supervised for Manager {}

impl SystemService for Manager {
    fn service_started(&mut self, _ctx: &mut Context<Self>) {}
}

struct Work {}

#[derive(Message)]
#[rtype(result = "()")]
struct PerformWork(Work);

#[derive(Message)]
#[rtype(result = "()")]
pub struct ReportProgress(i32);

impl Handler<PerformWork> for Worker {
    type Result = ();

    fn handle(&mut self, msg: PerformWork, ctx: &mut Self::Context) -> Self::Result {
        for i in 0..10000000 {
            // Report progress
            Manager::from_registry().do_send(ReportProgress(i));
            // Do some very slow I/O.
            thread::sleep(time::Duration::from_millis(1));
        }
    }
}

impl Handler<ReportProgress> for Manager {
    type Result = ();

    fn handle(&mut self, msg: ReportProgress, ctx: &mut Self::Context) -> Self::Result {
        // Do something with the progress here
    }
}

Manager还处理将Message PerformWork发送到Message的{{1}}。

我想到给Worker ReportProgress一个布尔值返回类型，该类型允许Message决定是否应该退出循环。但是，我无法管理将具有返回值/结果的Worker发送到Message。使用Manager代替send()会返回do_send()，我无法在Future内解析。

非常感谢任何想法。

更多背景信息：

真正慢的I / O是串行通信。
actix的版本为0.10

Answer 1

我找到了一种解决方案，但我不认为这是一个好方法。

我添加了一个Arc<AtomicBool>>并传递给Worker。 Manager保留对布尔值的引用并可以对其进行修改。如果Worker修改了布尔值，则Manager会跳出循环。

use actix::prelude::*;
use std::sync::atomic::{AtomicBool, Ordering};

struct Worker {}

impl Actor for Worker {
    type Context = SyncContext<Self>;
}

struct Manager {
    worker: Addr<Worker>,
}

impl Actor for Manager {
    type Context = Context<Self>;
}

impl Supervised for Manager {}

impl SystemService for Manager {
    fn service_started(&mut self, _ctx: &mut Context<Self>) {}
}

struct Work {}

#[derive(Message)]
#[rtype(result = "()")]
struct PerformWork(Work, Arc<AtomicBool>>);

#[derive(Message)]
#[rtype(result = "()")]
pub struct ReportProgress(i32);

impl Handler<PerformWork> for Worker {
    type Result = ();

    fn handle(&mut self, msg: PerformWork, ctx: &mut Self::Context) -> Self::Result {
        for i in 0..10000000 {
            // Report progress
            Manager::from_registry().do_send(ReportProgress(i));
            if msg.1.load(Ordering::Relaxed) {
                break;
            }
            // Do some very slow I/O.
            thread::sleep(time::Duration::from_millis(1));
        }
    }
}

impl Handler<ReportProgress> for Manager {
    type Result = ();

    fn handle(&mut self, msg: ReportProgress, ctx: &mut Self::Context) -> Self::Result {
        // Do something with the progress here
    }
}

如何从actix SyncContext向其他角色发送消息？

1 个答案: