Question

im试图获得如下所示的结果

### ###
#2# #3#
### ###

first = 2
second = 3
if first == 2:
  print('###', end=" ")
  print('#2#', end=" ")
  print('###', end=" ")
if second == 3:
  print('###', end=" ")
  print('#3#', end=" ")
  print('###', end=" ")

我无法让他们像我想要的那样彼此相邻，这也适用于数字1到11，所以我不能只做if first == 2 and second == 3:那样行太多了

Answer 1

您可以使用for循环执行任务：

first = 2
second = 3

for current in range(first, second+1):
    print('###', end=' ')
print()
for current in range(first, second+1):
    print('#{}#'.format(current), end=' ')
print()
for current in range(first, second+1):
    print('###', end=' ')
print()

打印：

### ### 
#2# #3# 
### ###

针对：

first = 2
second = 6

它打印：

### ### ### ### ### 
#2# #3# #4# #5# #6# 
### ### ### ### ###

编辑：仅打印两个数字：

first = 2
second = 6

print('### ###')
print('#{}# #{}#'.format(first, second))
print('### ###')

打印：

### ###
#2# #6#
### ###

Answer 2

更紧凑，可读性和可维护性的选项：

first = 2
second = 7

def doLine(s):
    for i in range(first, second+1):
        print(s.format(i), end=' ')
    print()

doLine('###')
doLine('#{}#')
doLine('###')

结果：

### ### ### ### ### ### 
#2# #3# #4# #5# #6# #7# 
### ### ### ### ### ###

如何在同一行上打印if语句

2 个答案: