数据框:
A B
1 a c
2 x x
3 t q
4 l l
5 w y
6 b b
我想添加一列来检测匹配项或不匹配项:
A B C
1 a c miss
2 x x match
3 t q miss
4 l l match
5 w y miss
6 b b match
答案 0 :(得分:1)
基本R选项
transform(
df,
C = c("miss","match")[(A==B)+1]
)
给予
A B C
1 a c miss
2 x x match
3 t q miss
4 l l match
5 w y miss
6 b b match
数据
> dput(df)
structure(list(A = c("a", "x", "t", "l", "w", "b"), B = c("c",
"x", "q", "l", "y", "b")), class = "data.frame", row.names = c("1",
"2", "3", "4", "5", "6"))
答案 1 :(得分:0)
> dd %>% rowwise() %>% mutate(match = case_when(A == B ~ 'match', TRUE ~ 'miss'))
# A tibble: 6 x 3
# Rowwise:
A B match
<chr> <chr> <chr>
1 a c miss
2 x x match
3 t q miss
4 l l match
5 w y miss
6 b b match
> dd
# A tibble: 6 x 2
A B
<chr> <chr>
1 a c
2 x x
3 t q
4 l l
5 w y
6 b b
>
答案 2 :(得分:0)
带有索引的const requestAll = async () => {
return await Promise.all(requestItems.map(async url => {
try {
return await apiService.get(url);
} catch (err) {
console.log(err)
}
}));
}
选项(虽然 @ThomasIsCoding 是更专业的解决方案):
base R
输出:
#Code
index <- df$A==df$B
df$C <- 'miss'
df$C[index]<-'match'
使用了一些数据:
df
A B C
1 a c miss
2 x x match
3 t q miss
4 l l match
5 w y miss
6 b b match