Question

我正在尝试使用继承格式方法格式化十六进制字符串。我有点像Ruby-noob，感谢任何帮助。

class Bar
  def alter_the_variable attribute_name
    attribute = method(attribute_name)
    formatted = "%.4x" % attribute.call.hex
    puts formatted    # => 00f3
    attribute = formatted   # What I "want" to be able to do, but
                            # doesn't work because attribute is a local variable

    #attribute.owner.send(:h=, formatted)   # Doesn't work either, gives:
                                            # in `send': undefined method `h=' for Foo:Class (NoMethodError)
  end
end

class Foo < Bar
  def initialize
    @h = "f3"
  end

  def h
    @h
  end

  def h= val
    @h = val
  end
end

f = Foo.new
puts f.h    # => f3
f.alter_the_variable :h
puts f.h    # => f3

Answer 1

这是一种做你想做的事情的方法：

def alter_the_variable attribute_name
  current_value = send(attribute_name)
  formatted_value = "%.4x" % current_value.hex
  send (attribute_name.to_s+'=').to_sym, formatted_value
end

Ruby：具有继承的动态setter

1 个答案: