Question

我遇到的情况是，如果给定的字符串的引号"为奇数，则最后一个引号必须替换为空字符串。这是我遵循的方法来实现的代码，但是它不能替换字符串，任何人都可以帮我吗？

const input = `"hello,"sai,sur",ya,teja`;
let output = "";
if(evenOrOdd(input.split(`"`) == "even")){
 //Here the last occurrence which needed to be replaced with empty string
 input[input.split(`"`).lastIndexOf(`"`)] = "";
 console.log(input);
  output = input.replace(/"([^"]+)"/g, (_, g) => g.replace(',', '-'))
}else{
 output = input.replace(/"([^"]+)"/g, (_, g) => g.replace(',', '-'))
}


console.log(output);

function evenOrOdd(number){
//check if the number is even
if(number % 2 == 0) {
    console.log("The number is even.");
    
    return "even";
}

// if the number is odd
else {
    console.log("The number is odd.");
    return "odd";
   }
}

Thanks in advance :)

Answer 1

您可以如下替换：

const input = `"hello,"sai,sur",ya,teja`;
const idx = input.lastIndexOf('"');
const result = input.substr(0, idx) + input.substr(idx+1)


console.log(result);

Answer 2

尝试这样：

const input = `"hello,"sai,sur",ya,teja`;

let output = "";
let lastIndex = null;

if (evenOrOdd(input.split(`"`).length - 1) === "odd") {
  //Here the last occurrence which needed to be replaced with empty string
  lastIndex = input.lastIndexOf(`"`)
  output = input.substring(0, lastIndex) + input.substring(lastIndex + 1)
}

console.log(output);

function evenOrOdd(number) {
  //check if the number is even
  if (number % 2 == 0) {
    console.log("The number is even.");

    return "even";
  }

  // if the number is odd
  else {
    console.log("The number is odd.");
    return "odd";
  }
}

在调用evenOrOdd函数时，需要提供出现次数，然后将结果检查为"odd"或"even"。如果是偶数，那么我们就完成了。我们只想替换最后一次出现的奇数。我们可以简单地通过字符串中的位置（索引）来执行此操作。之后似乎不需要用正则表达式替换。

字符串操作以删除最后一次出现的字符“”

2 个答案: