Question

我有一个与Firebase交互的AuthService类。然后在Signin.dart中，我想获得该用户，但是每次获得用户时遇到问题。我收到错误消息，表明Firebase无法发送用户。

错误：

发生异常。 PlatformException （PlatformException（firebase_auth， com.google.firebase.FirebaseException：发生内部错误。 [错误403（禁止）！1
* {margin：0; padding：0} html，code {font：15px / 22px arial，sans-serif} html {background：#fff; color：＃222; padding：15px} body {margin：7％自动0；最大宽度：390像素；最小高度：180像素；填充：30像素0 15像素} *> 正文{background：url（// www.google.com/images/errors/robot.png）100％5px no-repeat; padding-right：205px} p {margin：11px 0 22px；溢出：隐藏} ins {颜色：＃777;文本装饰：无} a img {border：0} @media屏幕和（max-width：772px）{body {background：none; margin-top：0; max-width：none; padding-right：0}}＃logo {background：url（// www.google.com/images/ branding / googlelogo / 1x / googlelogo_color_150x54dp.png） no-repeat; margin-left：-5px} @media only屏幕和（最低分辨率：192dpi）{＃logo {background：url（// www.google.com/images/branding/googlelogo/2x/googlelogo_color_150x54dp.png）不可重复0％0％/ 100％ 100％;-moz-border-image：url（// www.google.com/images/branding/googlelogo/2x/googlelogo_color_150x54dp.png） 0}} @仅媒体屏幕和（-webkit-min-device-pixel-ratio：2）{＃logo {background：url（// www.google.com/images/branding/googlelogo/2x/googlelogo_color_150x54dp.png）禁止重复; -webkit-background-size：100％ 100％}}＃logo {display：inline-block; height：54px; width：150px}

403。这是一个错误。

您的客户不有权获取URL import 'package:firebase_auth/firebase_auth.dart'; class AuthService { final FirebaseAuth _auth = FirebaseAuth.instance; // sign in anon Future signInAnon() async { try { UserCredential userCredential = await _auth.signInAnonymously(); User user = userCredential.user; return user; } catch (e) { print(e.toString()); return null; } } // sign in with email and password // register with email and password // sign out }从这里服务器。我们知道的就这些。 ]， {}，空值））

import 'package:auth_flutter_coffe/Services/Auth.dart';
import 'package:flutter/material.dart';

class SignIn extends StatefulWidget {
  @override
  _SignInState createState() => _SignInState();
}

class _SignInState extends State<SignIn> {
  final AuthService _auth = AuthService();

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      backgroundColor: Colors.brown[700],
      appBar: AppBar(
        title: Text("SignIn"),
        centerTitle: true,
        backgroundColor: Colors.brown[900],
      ),
      body: Container(
        padding: EdgeInsets.symmetric(horizontal: 50.0, vertical: 50.0),
        child: RaisedButton.icon(
            onPressed: () async {
              dynamic result = await _auth.signInAnon();
              if (result == null) {
                print("You Have to be SignIn");
              } else {
                print("SignIn");
                print(result);
              }
            },
            icon: Icon(Icons.transit_enterexit),
            label: Text("SignIn")),
      ),
    );
  }
}

SignIn.dart

class ViewController: UIViewController {

@IBOutlet weak var sampImage: UIImageView!
override func viewDidLoad() {
    super.viewDidLoad()
    
    let tapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(imageTapped(tapGestureRecognizer:)))
    sampImage.isUserInteractionEnabled = true
    sampImage.addGestureRecognizer(tapGestureRecognizer)
    }


@objc func imageTapped(tapGestureRecognizer: UITapGestureRecognizer)
{
let tappedImage = tapGestureRecognizer.view as! UIImageView
let newImageView = UIImageView(image: tappedImage.image)
newImageView.frame = UIScreen.main.bounds
newImageView.backgroundColor = .black
newImageView.contentMode = .scaleAspectFit
newImageView.isUserInteractionEnabled = true
let tap = UITapGestureRecognizer(target: self, action: #selector(dismissFullscreenImage))
newImageView.addGestureRecognizer(tap)
self.view.addSubview(newImageView)
self.navigationController?.isNavigationBarHidden = true
self.tabBarController?.tabBar.isHidden = true
}

@objc func dismissFullscreenImage(_ sender: UITapGestureRecognizer) {
self.navigationController?.isNavigationBarHidden = false
self.tabBarController?.tabBar.isHidden = false
sender.view?.removeFromSuperview()
}
}

Answer 1

在google-service.json和build.gradle文件中检查项目的ID必须相同。

Firebase不会返回用户

1 个答案: