Question

我有以下对象数组：

const array = [
    {
        "id":1,
        "environment":"ENV1",
        "other_key":"other_value"
    },
    {
        "id":2,
        "environment":"ENV1",
        "other_key":"other_value_two"
    },
    {
        "id":3,
        "environment":"ENV2",
        "other_key":"other_value_three"
    }
]

现在，如果数组的环境值不同，则需要显示警报。如果所有环境都相同，则无需显示警报。在上面的示例中，我需要显示警告警报。

如何检查特定键的数组是否包含不同的值或具有相同的值？

Answer 1

我认为您可以这样做：

const array = [
    {
        "id":1,
        "environment":"ENV1",
        "other_key":"other_value"
    },
    {
        "id":2,
        "environment":"ENV1",
        "other_key":"other_value_two"
    },
    {
        "id":3,
        "environment":"ENV2",
        "other_key":"other_value_three"
    }
]

const everyEnvHasSameValue = array.every( ({other_key}) => other_key === array[0].other_key); // use proper name

console.log(everyEnvHasSameValue);

Answer 2

我只在这里使用过滤器：

const array = [
    {
        "id":1,
        "environment":"ENV1",
        "other_key":"other_value"
    },
    {
        "id":2,
        "environment":"ENV1",
        "other_key":"other_value_two"
    },
    {
        "id":3,
        "environment":"ENV1",
        "other_key":"other_value_three"
    }
]

const el = array.filter(e => e.environment !== array[0].environment)
if(el.length > 0) alert('envs are diff')

如何检查对象数组是否包含特定键的相同值

2 个答案: