我是Flutter的初学者,并且是第一次使用Futurebuilder和provider。最后,我创建了一个添加地点的应用程序。使用以下代码,我几乎实现了该应用程序。但是现在出现了一个小问题。当应用程序从提供程序获取数据时,它会显示浮动操作按钮。我不希望那样有什么方法可以在获取数据时隐藏浮动操作按钮,并在从数据库中获取数据后将其显示给用户?
import 'package:flutter/material.dart';
import 'package:provider/provider.dart';
import './add_place_screen.dart';
import '../providers/great_places.dart';
import './place_detail_screen.dart';
class PlacesListScreen extends StatelessWidget {
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text('Your Places'),
actions: <Widget>[
IconButton(
icon: Icon(Icons.add),
onPressed: () {
Navigator.of(context).pushNamed(AddPlaceScreen.routeName);
},
),
],
),
body: FutureBuilder(
future: Provider.of<GreatPlaces>(context, listen: false)
.fetchAndSetPlaces(),
builder: (ctx, snapshot) => snapshot.connectionState ==
ConnectionState.waiting
? Center(
child: CircularProgressIndicator(),
)
: Consumer<GreatPlaces>(
child: Center(
child: const Text('Got no places yet, start adding some!'),
),
builder: (ctx, greatPlaces, ch) => greatPlaces.items.length <= 0
? ch
: ListView.builder(
itemCount: greatPlaces.items.length,
itemBuilder: (ctx, i) => ListTile(
leading: CircleAvatar(
backgroundImage: FileImage(
greatPlaces.items[i].image,
),
),
title: Text(greatPlaces.items[i].title),
subtitle:
Text(greatPlaces.items[i].location.address),
onTap: () {
Navigator.of(context).pushNamed(
PlaceDetailScreen.routeName,
arguments: greatPlaces.items[i].id,
);
},
),
),
),
),
floatingActionButton: FloatingActionButton(
onPressed: () {
},
child: Icon(Icons.add),
),
);
}
}
答案 0 :(得分:1)
使您的班级成为 StatefulWidget ,而不是 StatelessWidget 。这将有助于实现“浮动操作按钮”的可见性。并尝试在构建方法中处理setstate(){},该方法会在状态变化时不断调用。
答案 1 :(得分:0)
您可以尝试ValueNotifier,https://api.flutter.dev/flutter/foundation/ValueNotifier-class.html
一个拥有单个值的ChangeNotifier。
当用相等运算符==评估的值替换为不等于旧值的值时,此类会通知其侦听器。
import 'package:flutter/material.dart';
import 'package:provider/provider.dart';
import './add_place_screen.dart';
import '../providers/great_places.dart';
import './place_detail_screen.dart';
class PlacesListScreen extends StatelessWidget {
final ValueNotifier<bool> _isWaiting = ValueNotifier<bool>(false);
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text('Your Places'),
actions: <Widget>[
IconButton(
icon: Icon(Icons.add),
onPressed: () {
Navigator.of(context).pushNamed(AddPlaceScreen.routeName);
},
),
],
),
body: FutureBuilder(
future: Provider.of<GreatPlaces>(context, listen: false)
.fetchAndSetPlaces(),
builder: (ctx, snapshot) {
_isWaiting.value =
snapshot.connectionState == ConnectionState.waiting;
return _isWaiting.value
? Center(
child: CircularProgressIndicator(),
)
: Consumer<GreatPlaces>(
child: Center(
child:
const Text('Got no places yet, start adding some!'),
),
builder: (ctx, greatPlaces, ch) =>
greatPlaces.items.length <= 0
? ch
: ListView.builder(
itemCount: greatPlaces.items.length,
itemBuilder: (ctx, i) => ListTile(
leading: CircleAvatar(
backgroundImage: FileImage(
greatPlaces.items[i].image,
),
),
title: Text(greatPlaces.items[i].title),
subtitle: Text(
greatPlaces.items[i].location.address),
onTap: () {
Navigator.of(context).pushNamed(
PlaceDetailScreen.routeName,
arguments: greatPlaces.items[i].id,
);
},
),
),
);
}),
floatingActionButton: ValueListenableBuilder(
valueListenable: _isWaiting,
builder: (BuildContext context, bool value, Widget child) {
return Visibility(
visible: !value,
child: FloatingActionButton(
onPressed: () {},
child: Icon(Icons.add),
));
}),
);
}
}
答案 2 :(得分:0)
1