Question

我的目标是在TEMP表（CTE）中填充NULL。例如，有3手。其中有两个批次在RECIPE栏中具有价值。但是L3批次没有。但是，材料恰好具有相同的值。因此，在这种情况下，我可以填写相同的值（在这种情况下为“ R1”）。如何在我的代码中修改WITH子句？

Expected result is 

"LOTNO" "MATERIAL"  "RECIPE"
------- ---------- --------
"L1"    "M1"    "R1"
"L2"    "M1"    "R1"
"L3"    "M1"    "R1"

我的代码是

 CREATE TABLE OUTHISTORY (LOTNO VARCHAR(10), MATERIAL VARCHAR(10), RECIPE VARCHAR(10));
    INSERT INTO OUTHISTORY VALUES('L1','M1','R1');
    INSERT INTO OUTHISTORY VALUES('L2','M1','R1');
    INSERT INTO OUTHISTORY VALUES('L3','M1',NULL);
    
    WITH TEMP AS (
    SELECT * FROM OUTHISTORY  --How to modify here?
    ) SELECT * FROM TEMP;

Answer 1

重新使用with子句以获取与recipe相同的material值，

with temp 
as 
(
  select * 
    from outhistory  --How to modify here?
),
temp_with_filled_null
as
(
select lotno,material,
 coalesce (recipe
          ,(select recipe
              from temp i
             where i.lotno != o.lotno
               and i.material = o.material
               and rownum = 1)) recipe
  from temp o
)
select *
  from temp_with_filled_null;

在这里您可以避免使用第二个with子句，但是我建议这样做，如果您使用> = 12c，第二个可以使用FETCH FIRST ROW的{{1}} insta

根据其他数据自动填写

1 个答案: