Question

如何加入这两个查询以获取一个结果中的所有表格信息？

A - 获取属于表Customers

的所有列及其数据类型

select COLUMN_NAME, DATA_TYPE from INFORMATION_SCHEMA.COLUMNS where TABLE_NAME = 'Customers'

B - 获取表格中的所有约束

SELECT        KCU1.CONSTRAINT_NAME AS 'ConstraintName', KCU1.COLUMN_NAME AS 'ColumnName', KCU2.TABLE_NAME AS 'ForeignTableName', 
                             KCU2.COLUMN_NAME AS 'ForeignColumnName'
    FROM            INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS AS RC INNER JOIN
                             INFORMATION_SCHEMA.KEY_COLUMN_USAGE AS KCU1 ON KCU1.CONSTRAINT_CATALOG = RC.CONSTRAINT_CATALOG AND 
                             KCU1.CONSTRAINT_SCHEMA = RC.CONSTRAINT_SCHEMA AND KCU1.CONSTRAINT_NAME = RC.CONSTRAINT_NAME INNER JOIN
                             INFORMATION_SCHEMA.KEY_COLUMN_USAGE AS KCU2 ON KCU2.CONSTRAINT_CATALOG = RC.UNIQUE_CONSTRAINT_CATALOG AND 
                             KCU2.CONSTRAINT_SCHEMA = RC.UNIQUE_CONSTRAINT_SCHEMA AND KCU2.CONSTRAINT_NAME = RC.UNIQUE_CONSTRAINT_NAME AND 
                             KCU2.ORDINAL_POSITION = KCU1.ORDINAL_POSITION AND KCU1.TABLE_NAME = 'Customers'

我想要的结果是所有列的列表，那些与另一个表有外键连接的列应该这样表示。（抱歉我的术语很差）

Answer 1

啊！得到它了！这是：

SELECT        CL.COLUMN_NAME AS 'ColumnName', CL.DATA_TYPE AS 'DataType', CL.CHARACTER_MAXIMUM_LENGTH AS 'MaxLength', 
                         KCU1.CONSTRAINT_NAME AS 'ConstraintName', KCU2.TABLE_NAME AS 'ForeignTableName', KCU2.COLUMN_NAME AS 'ForeignColumnName'
FROM            INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS AS RC INNER JOIN
                         INFORMATION_SCHEMA.KEY_COLUMN_USAGE AS KCU1 ON KCU1.CONSTRAINT_CATALOG = RC.CONSTRAINT_CATALOG AND 
                         KCU1.CONSTRAINT_SCHEMA = RC.CONSTRAINT_SCHEMA AND KCU1.CONSTRAINT_NAME = RC.CONSTRAINT_NAME INNER JOIN
                         INFORMATION_SCHEMA.KEY_COLUMN_USAGE AS KCU2 ON KCU2.CONSTRAINT_CATALOG = RC.UNIQUE_CONSTRAINT_CATALOG AND 
                         KCU2.CONSTRAINT_SCHEMA = RC.UNIQUE_CONSTRAINT_SCHEMA AND KCU2.CONSTRAINT_NAME = RC.UNIQUE_CONSTRAINT_NAME AND 
                         KCU2.ORDINAL_POSITION = KCU1.ORDINAL_POSITION AND KCU1.TABLE_NAME = 'Customers' RIGHT OUTER JOIN
                         INFORMATION_SCHEMA.COLUMNS AS CL ON KCU1.TABLE_NAME = CL.TABLE_NAME AND KCU1.COLUMN_NAME = CL.COLUMN_NAME
WHERE        (CL.TABLE_NAME = N'Customers')
ORDER BY CL.ORDINAL_POSITION

选择列信息并使用约束信息加入

1 个答案: