Question

我正在尝试创建一个列表，该列表仅允许用户在进入编辑模式后删除。我试图在onDelete修饰符中尝试使用三元运算，但是无法弄清楚。有什么建议吗？

这是我的代码：

struct ContentView: View {
    @State private var stuff = ["First", "Second", "Third"]
    @State private var check = false
    
    var body: some View {
        Form {
            Button(action: { check.toggle() }, label: { Text(check ? "Editing" : "Edit") })
            
            ForEach(0..<stuff.count) { items in
                Section{ Text(stuff[items]) }
            }
             .onDelete(perform: self.deleteItem)
               
        }
    }
    
    private func deleteItem(at indexSet: IndexSet) {
        self.stuff.remove(atOffsets: indexSet)
    }
}

Answer 1

我认为您正在寻找以下内容

var body: some View {
    Form {
        Button(action: { check.toggle() }, label: { Text(check ? "Editing" : "Edit") })
        
        ForEach(0..<stuff.count) { items in
            Section{ Text(stuff[items]) }
        }
         .onDelete(perform: self.deleteItem)
         .deleteDisabled(!check)             // << this one !!
    }
}

Answer 2

struct ContentView: View {
    @State private
    var stuff = ["First", "Second", "Third"]
    var body: some View {
        NavigationView {
            Form {
                ForEach(0..<stuff.count) { item in
                    Section {
                        Text(stuff[item])
                    }
                }
                .onDelete(
                    perform: delete)
            }
            .navigationBarItems(
                trailing:
                    EditButton()
            )
            .navigationTitle("Test")
        }
    }
}

extension ContentView {
    private func delete(at indexSet: IndexSet) {
        stuff.remove(atOffsets: indexSet)
    }
}

SwiftUI：有条件的onDelete

2 个答案: