我正在尝试将城市名称数组添加到本地化json文件中,但在将其转换为字符串后无法将其解码回数组。
en-US.json
{
"title" : "My account",
"name" : "John",
"cities" : ["Paris", "Lyon", "Nice"]
}
AppLocalization.dart
class AppLocalizations {
final Locale locale;
AppLocalizations(this.locale);
static AppLocalizations of(BuildContext context) {
return Localizations.of<AppLocalizations>(context, AppLocalizations);
}
static const LocalizationsDelegate<AppLocalizations> delegate =
_AppLocalizationsDelegate();
Map<String, String> _localizationStrings;
Future<bool> load() async {
String jsonString = await rootBundle.loadString(
'assets/translations/${locale.languageCode}-${locale.countryCode}.json');
Map<String, dynamic> jsonMap = json.decode(jsonString);
_localizationStrings = jsonMap.map((key, value) {
return MapEntry(key, value.toString());
});
return true;
}
Future<void> setLocale(Locale locale) async {
final SharedPreferences _prefs = await SharedPreferences.getInstance();
final _languageCode = locale.languageCode;
await _prefs.setString('locale', _languageCode);
print('locale saved!');
}
static Future<Locale> getLocale() async {
final SharedPreferences _prefs = await SharedPreferences.getInstance();
final String _languageCode = _prefs.getString('locale');
if (_languageCode == null) return null;
Locale _locale;
_languageCode == 'en'
? _locale = Locale('en', 'US')
: _locale = Locale('ar', 'EG');
return _locale;
}
String translate(String key) {
return _localizationStrings[key];
}
}
class _AppLocalizationsDelegate
extends LocalizationsDelegate<AppLocalizations> {
const _AppLocalizationsDelegate();
@override
bool isSupported(Locale locale) {
return ['en', 'ar'].contains(locale.languageCode);
}
@override
Future<AppLocalizations> load(Locale locale) async {
AppLocalizations localization = AppLocalizations(locale);
await localization.load();
return localization;
}
@override
bool shouldReload(LocalizationsDelegate<AppLocalizations> old) {
return false;
}
}
在我的小部件中,我尝试通过List<String> _cities = AppLocalization.of(context).translate('cities');
这有效,并且如果我打印_cities.toString(),它将打印[巴黎,里昂,尼斯]。
问题
当我尝试使用json.decode(_cities)
将_cities解码为数组时,总是出现格式错误未处理的异常:FormatException:意外的字符(在字符2)。
我相信此函数会将数组转换为String
_localizationStrings = jsonMap.map((key, value) {
return MapEntry(key, value.toString());
});
如何将其解析回数组?
我愿意接受各种建议。谢谢
答案 0 :(得分:0)
如果要以数组形式访问本地化数据,请不要将数组展平为字符串。视您的用例而定,将这种数据始终存储在本地化文件中可能不合适。
但是,如果您仍然希望将列表存储在本地化文件中,那么我建议您不要展平解码的json映射并返回动态值,而不是从translate
返回String。当您检索本地化的值时,必须将其类型转换为所需的类型,因此您可能需要添加一些辅助函数(请参见下文)以使其稍干。
import 'dart:convert';
var cities = '''
{
\"cities\" : [\"Paris\", \"Lyon\", \"Nice\"]
}
''';
class Localization {
final Map<String,dynamic> data;
Localization(this.data);
String localizedString(String key) {
return data[key] as String;
}
List<String> localizedList(String key) {
return List<String>.from(data[key]);
}
}
void main(){
var data = jsonDecode(cities); // jsonDecode(cities);
var l = Localization(data);
for(var city in l.localizedList("cities")) {
print("$city");
}
}
答案 1 :(得分:0)
我知道这可能不是执行此操作的最佳方法,但这只是我发现的一种方法。您还可以将值保存在其他json资产文件中,并通常使用json.decode()对其进行解析,但我需要使用它来通过本地化更轻松地处理它。
因此我找到了一个简单的解决方案,而不是向本地化类添加功能。
我从本地化文件中以字符串形式从数组中获取数组中的数组(就像其他任何本地化字符串一样):
var list = AppLocalization.of(context).translate('cities');//this will return [Paris, Lyon, Nice] as a string
然后我执行以下操作:
list = list.replaceAll(RegExp("\\[|\\]"), ''); //removes square brackets from the string
var cityList = list.split(','); //splits the city names by the comma as a
print(cityList); //prints [Paris, Lyon, Nice] as List<String>
我还实现了另一种获取嵌套json数组的方法,如
{
"title" : "My account",
"name" : "John",
"cities" : ["Paris", "Lyon", "Nice"],
"areas" :
{
"paris" : ["area1", "area2", "area3"],
"lyon": ["area1", "area2", "area3"]
}
}
我这样做是为了获得巴黎地区...
var areas = AppLocalization.of(context).translate('areas'); //this gets the whole map as a string.
areas = areas.replaceAll(RegExp("\\[|\\]|\\{|\\}"), '');//this removes leading and trailing {[ ]}
var splitValues = areas.split(':');
var mapValues = Map.fromIterable(test, key: (item) => splitValues[0],value: (item) => item.split(','),);
var parisAreas = mapValues.map((key, value) =>
MapEntry<String, List<String>>(key, List<String>.from(value)));