将jq的输出组合到每个记录输出的单行中

Question

我目前有jq的输出，如下所示：

1§
{"id":"1","name":"River Street , Clerkenwell","lastUpdate":"1601461560941"}
2§
{"id":"2","name":"Phillimore Gardens, Kensington","lastUpdate":"1601461560941"}

，我希望它加入每条记录的输出行，即：

1§{"id":"1","name":"River Street , Clerkenwell","lastUpdate":"1601461560941"}
2§{"id":"2","name":"Phillimore Gardens, Kensington","lastUpdate":"1601461560941"}

以下是示例输入和当前过滤器：https://jqplay.org/s/qBfGyriA5B

如果我使用-j，则所有内容都在同一行，这不是我想要的

1§{"id":"1","name":"River Street , Clerkenwell","lastUpdate":"1601461560941"}2§{"id":"2","name":"Phillimore Gardens, Kensington","lastUpdate":"1601461560941"}

Answer 1

一种方法是在创建的对象上通过空字符串使用join函数。请注意，您要创建的对象需要转换为字符串类型才能起作用。在--raw-output/-r模式下使用以下过滤器

.stations.station[] + { lastUpdate: .stations."@lastUpdate" } | 
[ .id + "§", tostring ] | 
join("")

^{jqplay demo}