Question

我编写了以下内容，以自动将文本从不断更新的.txt文件解析为电报机器人。

import urllib.parse
import time
import requests


def post_to_telegram(msg):
    print(msg)
    base_url = 'https://api.telegram.org/bot&text="{}"'.format(msg)
    requests.get(base_url)

urr = ""
name = ""
price = ""
ourLines=0
while(True):
    file1 = open('example.txt', 'r')
    Lines = file1.readlines()
    time.sleep(1)
    while(True):
        if(ourLines==len(Lines)):
            break
        else:
            txt = Lines[ourLines].strip()
            tlist = txt.split("&")
            ourLines=ourLines+1
            for subtxt in tlist:
                if "eventurl=" in subtxt:
                    a = subtxt[9:len(subtxt) - 3]
                    url = 'www.bbey43.com/#'+a.replace("%23", "/")
                    #print(url)
                    urr = url
                elif "bet=" in subtxt:
                    name = urllib.parse.unquote(subtxt[4:len(subtxt)])
                    #print(name)
                elif "price\":" in subtxt:
                    a = subtxt.split("price")[1]
                    price = a.split("\"")[2]
                    #print(price)
            post_to_telegram(urr + " "+ name + " " + price)

“名称”和“价格”已成功发布到机器人，但“ url”未正确发布。唯一通过的是“ bbey43.com /＃/

Answer 1

最后，解决这个问题的方法很简单。由于“＃”是URL的一部分，因此在解析时需要特殊的格式。

只需添加％23而不是＃即可解决。

完整网址未正确解析为电报机器人

1 个答案: