我有一个功能组件,它使用onSubmit函数设置状态。问题在于setState函数不会及时更新用户状态,以便在将身份验证状态更改为true之前将其传递给用户prop。这是我组件的基本要点:
import React, { useState } from 'react';
import axios from 'axios';
import { LoginForm } from './LoginForm';
import { LoggedIn } from './LoggedIn';
const { login } = require('../utils/login');
const { getUser } = require('../utils/getUser');
export const Splash = () => {
const [user, setUser] = useState(null);
const [authenticated, setAuthenticated] = useState(false);
const [email, setEmail] = useState('');
const [password, setPassword] = useState('');
const _handleEmail = (e) => {
setEmail(e.target.value);
};
const _handlePass = (e) => {
setPassword(e.target.value);
};
const _handleSubmit = async (e) => {
e.preventDefault();
const token = await login(email, password);
const fetchUser = await getUser(token);
setAuthenticated(true);
setUser(fetchUser);
console.log(fetchUser) <---- logs user fine
console.log(user) <----- logs empty object
};
const _handleLogout = async (e) => {
const logout = await
axios.get('http://localhost:5000/api/v1/auth/logout');
console.log(
`Logout status: ${logout.status}, Success: ${logout.data.success}`
);
setAuthenticated(false);
setUser({});
};
return (
<div>
{!authenticated ? (
<LoginForm
handleEmail={_handleEmail}
handlePass={_handlePass}
handleSubmit={_handleSubmit}
/>
) : (
<LoggedIn
user={user}
authenticated={authenticated}
logout={_handleLogout}
/>
)}
</div>
);
};
无论出于何种原因,我的setAuthenticated函数都会将身份验证状态从false更改为true,从而触发<LoggedIn />
的呈现,但是我的用户状态不会及时更新以传递给<LoggedIn />
通过user
道具。我怀疑我发送的authenticated
道具也没有更新。有想法吗?
谢谢!
编辑:这是我的<LoggedIn />
组件,它是<LoggedInNav />
组件。
/// LoggedIn.js
export const LoggedIn = ({ logout, user, authenticated }) => {
LoggedIn.propTypes = {
logout: PropTypes.func.isRequired,
user: PropTypes.object.isRequired,
authenticated: PropTypes.bool.isRequired
};
const [loggedInUser, setUser] = useState({});
const [loggedInAuth, setAuthenticated] = useState(false);
useEffect(() => {
try {
if (user) {
setAuthenticated(true);
setUser(user);
}
} catch (err) {
console.log(err);
}
}, []);
return (
<div>
{!authenticated ? (
<Spinner animation='border' variant='primary' />
) : (
<LoggedinNav navUser={user} logoutButton={logout} />
)}
</div>
);
};
// LoggedInNav.js
export const LoggedinNav = ({ navUser, logoutButton }) => {
LoggedinNav.propTypes = {
navUser: PropTypes.object.isRequired,
logoutButton: PropTypes.func.isRequired
};
return (
<div>
<Navbar bg='light' variant='light'>
<Navbar.Brand href='#home'>
<img
src={logo}
width='120'
height='auto'
className='d-inline-block align-top ml-3'
alt='React Bootstrap logo'
/>
</Navbar.Brand>
<Nav className='mr-auto'>
<Nav.Link href='#feedback'>Submit Feedback</Nav.Link>
</Nav>
<Navbar.Collapse className='justify-content-end mr-4'>
<Navbar.Text>
Signed in as: {navUser.name.first} {navUser.name.last} - Role:{' '}
{navUser.role}
</Navbar.Text>
</Navbar.Collapse>
<Button onClick={logoutButton} variant='outline-primary mr-4'>
Logout
</Button>
</Navbar>
</div>
);
};
答案 0 :(得分:0)
根据React Docs,useState与setState相同,将触发新的渲染。
下一次渲染时,新值将在user
中。
因为您使用的是异步方法,所以您将退出循环,并且无法在下一行看到新的状态值。
请参见codesandbox poc:
在其中,异步功能等待2秒钟,然后设置状态。
您可以在控制台中看到,渲染在设置状态之后触发,渲染看到新状态,但是async方法将打印旧状态。
useState与setState一样,是同步的,这意味着它们将直接触发渲染。
对于异步工作,您可以使用useEffect