使用邮递员向nodejs whit发送请求时出错?

时间:2020-09-20 15:05:49

标签: node.js json express post postman

我正在尝试使用NodeJs将数据插入MYSql表中,Express框架使用POST方法抛出Postman。我得到一个错误。我不知道这是否与json的解析有关。否则我必须发送不同的邮件。

Json从邮递员发送(原始,JSON):

{
    "namel": "Teusaquillo",
    "area_2m": 6000,
    "parent": "chapinero"
}

我发送请求时出现此错误:

<pre>SyntaxError: Unexpected token   in JSON at position 3<br> &nbsp; &nbsp;at JSON.parse (&lt;anonymous&gt;)<br> &nbsp; &nbsp;at parse (<mypaht>\nodeapi\node_modules\body-parser\lib\types\json.js:89:19)<br> &nbsp; &nbsp;at <mypaht>\node_modules\body-parser\lib\read.js:121:18<br> &nbsp; &nbsp;at invokeCallback (<mypaht>nodeapi\node_modules\raw-body\index.js:224:16)<br> &nbsp; &nbsp;at done (<mypaht>\node_modules\raw-body\index.js:213:7)<br> &nbsp; &nbsp;at IncomingMessage.onEnd (<mypaht>\node_modules\raw-body\index.js:273:7)<br> &nbsp; &nbsp;at IncomingMessage.emit (events.js:326:22)<br> &nbsp; &nbsp;at endReadableNT (_stream_readable.js:1252:12)<br> &nbsp`; &nbsp;at processTicksAndRejections (internal/process/task_queues.js:80:21)</pre>

该错误的其他视图:

SyntaxError: Unexpected token   in JSON at position 3
    at JSON.parse (<anonymous>)
    at parse (<mypaht>\node_modules\body-parser\lib\types\json.js:89:19)
    at <mypaht>\node_modules\body-parser\lib\read.js:121:18
    at invokeCallback (<mypaht>\node_modules\raw-body\index.js:224:16)
    at done (<mypaht>\node_modules\raw-body\index.js:213:7)
    at IncomingMessage.onEnd (<mypaht>\node_modules\raw-body\index.js:273:7)
    at IncomingMessage.emit (events.js:326:22)
    at endReadableNT (_stream_readable.js:1252:12)
    at processTicksAndRejections (internal/process/task_queues.js:80:21)

这是index.js文件:

const express = require('express');
const bodyParser = require('body-parser');
const app = express();
const mysql = require('mysql');
 
app.use(bodyParser.json());
 
//create database connection
const conn = mysql.createConnection({
  ...
});
 
//connect to database
conn.connect((err) =>{
  ...
});     

app.post('/api/locations',(req, res) => {
  let data = {namel: req.body.namel, area_2m: req.body.area_2m, parent: req.body.parent};  
  let sql = "INSERT INTO location SET ?";
  let query = conn.query(sql, data,(err, results) => {
    if(err) throw err;
    res.send(JSON.stringify({"status": 200, "error": null, "response": results}));
  });
});

这是我要填写的表格:

CREATE TABLE `location` (
  `namel` char(100) NOT NULL,
  `area_2m` int(11) DEFAULT NULL,
  `parent` char(100) DEFAULT NULL,
  PRIMARY KEY (`namel`),
  KEY `parent` (`parent`),
  CONSTRAINT `location_ibfk_1` FOREIGN KEY (`parent`) REFERENCES `location` (`namel`)
) 

我会很感激您的帮助。谢谢!

3 个答案:

答案 0 :(得分:1)

在邮递员中,确保您选择JSON(application / json)enter image description here

答案 1 :(得分:1)

查询传递的数据应该是数组吗?

const express = require('express');
const bodyParser = require('body-parser');
const app = express();
const mysql = require('mysql');
 
app.use(bodyParser.json());
 
//create database connection
const conn = mysql.createConnection({
  ...
});
 
//connect to database
conn.connect((err) =>{
  ...
});     

app.post('/api/locations',(req, res) => {
  // use destruction for easy reading
  let { namel, area_2m, parent } = req.body;
  // use mysql format to build query
  let sql = "INSERT INTO location SET ?";
  let value = [namel, area_2m, parent]
  let queryString = mysl.format(sql, value)
  let query = conn.query(queryString,(err, results) => {
    if(err) throw err;
    res.send(JSON.stringify({"status": 200, "error": null, "response": results}));
  });
});

答案 2 :(得分:0)

就我而言,这是由于多余的空白而发生的。一旦我摆脱了属性之间以及左括号和第一个键/属性之间的所有额外空白,它就起作用了。

我正在使用 express 运行 NodeJS,我猜 express.json 会抛出错误而不是修剪掉多余的空格,即使 json 中的多余空格是完全有效的 json。