我们在应用程序中创建了FlatList组件和“联系人”屏幕。我们想在“联系人”屏幕中图像的附近添加“心脏”图标。我们在所有项目附近添加了心脏图标。但是,如果我们按了其中一个图标,它会将它们的所有颜色更改为红色,而不仅仅是其中一个。我们要更改单击项的颜色。
我们的程序的屏幕截图:
这是我们的FlatList组件:
import React, { Component } from 'react';
import { View, Text, SafeAreaView, StyleSheet, FlatList, Image, TouchableOpacity,
TouchableWithoutFeedback, TextInput } from 'react-native';
import { Right, Icon } from 'native-base';
import data from '../../data';
export default class FlatListComponent extends Component {
state = {
text: '',
contacts: data,
like: false,
color: 'white',
}
toggleLike=()=>{
this.setState({
like: !this.state.like
})
if(this.state.like){
this.setState({
color: 'red',
})
}else{
this.setState({
color: 'white',
})
}
}
renderContactsItem = ({item, index}) => {
return (
<View style={[styles.itemContainer]}>
<Image
style={styles.avatar}
source={{ uri: item.image }} />
<View style={styles.textContainer}>
<Text style={[styles.name], {color: '#fafafa'}}>{item.first_name}</Text>
<Text style={{ color: '#fafafa' }}>{item.last_name}</Text>
</View>
<Right style={{justifyContent: 'center'}}>
<TouchableWithoutFeedback onPress={this.toggleLike}>
{/*{this.like ? (
<Icon name="heart" type='FontAwesome' style={{paddingRight: 10, fontSize: 30, color: 'red'}} />
) :
( <Icon name="heart" type='FontAwesome' style={{paddingRight: 10, fontSize: 30, color: 'white'}} /> )
}*/}
<Icon name='heart' type='FontAwesome' size={32} style={{color: this.state.color === "white" ? 'white' :'red', paddingRight: 10 }}/>
{/*<Icon name="heart" type='FontAwesome' style={{paddingRight: 10, fontSize: 30, color: this.state.color}} />*/}
</TouchableWithoutFeedback>
</Right>
</View>
);
}
searchFilter = text => {
const newData = data.filter(item => {
const listItems = `${item.first_name.toLowerCase()}`
return listItems.indexOf(text.toLowerCase()) > -1;
});
this.setState({
contacts: newData,
});
};
renderHeader = () => {
const {text} = this.state;
return (
<View style={styles.searchContainer}>
<TextInput
onChangeText = {text => {
this.setState ({
text,
});
this.searchFilter(text);
}}
value={text}
placeholder="Search..."
style={styles.searchInput} />
</View>
)
}
render() {
return (
<FlatList
ListHeaderComponent={this.renderHeader()}
renderItem={this.renderContactsItem}
keyExtractor={item => item.id}
data={this.state.contacts}
/>
);
}
}
const styles = StyleSheet.create({
itemContainer: {
flex: 1,
flexDirection: 'row',
paddingVertical: 10,
borderBottomWidth: 1,
borderBottomColor: '#eee'
},
avatar: {
width: 50,
height: 50,
borderRadius: 25,
marginHorizontal: 10,
},
textContainer: {
justifyContent: 'space-around',
},
name: {
fontSize: 16,
},
searchContainer: {
padding: 10
},
searchInput: {
fontSize: 16,
backgroundColor: '#f9f9f9',
padding: 10,
}
});
我们的“联系人”屏幕就是:
import React from 'react';
import 'SafeAreaView' from 'react-native';
import FlatList from './FlatList';
export default function Contact() {
<SafeAreaView style={{ flex: 1 }}>
<FlatList />
</SafeAreaView>
}
我们如何实现呢?
答案 0 :(得分:1)
我最近遇到了这个问题:)一种选择是使renderContactsItem
成为其自己的组件。例如:
const RenderContactsItem = ({item, index}) => {
const [like, setLike] = useState(false);
const [color, setColor] = useState("white");
const toggleLike = () => {
setLike(!like)
if(like) {
setColor("red");
} else {
setColor("white");
}
}
return (
<View style={[styles.itemContainer]}>
<Image
style={styles.avatar}
source={{ uri: item.image }} />
<View style={styles.textContainer}>
<Text style={[styles.name], {color: '#fafafa'}}>{item.first_name}</Text>
<Text style={{ color: '#fafafa' }}>{item.last_name}</Text>
</View>
<Right style={{justifyContent: 'center'}}>
<TouchableWithoutFeedback onPress={toggleLike}>
<Icon name='heart' type='FontAwesome' size={32} style={{color, paddingRight: 10 }}/>
</TouchableWithoutFeedback>
</Right>
</View>
);
}
在这种情况下,每个项目都管理自己的状态,因此设置like
不会为每个项目设置它。
另一种选择是用“ like”状态构建对象,并在按下心脏时设置值。例如:
state = {
text: '',
contacts: data,
like: {},
color: 'white', // You don't need this
}
然后,当您按下心脏时,您可以向toggleLike
发送index
,并按以下方式设置状态:
toggleLike = (index) => {
let newLike = {...this.state.like};
newLike[index] = !Boolean(newLike[index]);
this.setState({
like: newLike,
});
}
并根据like
状态的索引值有条件地渲染颜色,如下所示:
<Icon name='heart' type='FontAwesome' size={32} style={{color: this.state.like[index] ? 'red' :'white', paddingRight: 10 }}/>