Question

我是Java Spring的新手，有一个小问题。

我不想将employee_id（来自雇员实体）发送到正文部分（在Postman中）的分配实体。当前它正在运行，因为我正在将employee_id作为PathVariable发送，并且正在使用ResponseBody发送工作分配数据。

@PostMapping("/add/{employee_id}")
   public void addEmployee(@PathVariable(value = "employee_id", required = false) Long employee_id, 
             @RequestBody Assignment a) {

       Employee employeeById = employeeRepository.findById(employee_id)
               .orElseThrow(() -> new RuntimeException("Employee not found"));

       a.setEmployee(employeeById);
       assignmentRepository.addAssignment(a);
   }

它正在使用URL localhost：8080 / add / 35 。 35是employee_id，分配数据可以在（邮递员）的正文中发送。我想做的是，也将主体名发送到员工名中（因此该URL应该仅是/ add），但我无法使其正常工作。

喜欢：

{
  "employee_id": 35,
  "title": "abc"
}

编辑：

Assignment.java

public class Assignment {
   @Id
   @GeneratedValue(strategy = GenerationType.IDENTITY)
   private Integer id;

   @OneToOne(optional = false)
   @JoinColumn(name = "employee_id", nullable = false)
   private Employee employee;

   @Size(min = 3, max = 50)
   private String assignment_title;

   public Assignment() {
   }

   public Assignment(String assignment_title) {
       super();
       this.assignment_title = assignment_title;
   }

   public Integer getId() {
       return id;
   }

   public void setId(Integer id) {
       this.id = id;
   }

   public String getAssignment_title() {
       return assignment_title;
   }

   public void setAssignment_title(String assignment_title) {
       this.assignment_title = assignment_title;
   }

   public Employee getEmployee() {
       return employee;
   }

   public void setEmployee(Employee employee) {
       this.employee = employee;
   }
}

AssignmentService.java

   public void addAssignment(Assignment e) {
       AssignmentRepository.save(e);
   }

AssignmentRepository.java

public interface AssignmentRepository extends CrudRepository<Assignment, Integer>{
   
}

Employee.java

public class Employee{
   @Id
   @GeneratedValue(strategy = GenerationType.IDENTITY)
   private Integer id;
   
   @OneToOne(optional = false)
   @JoinColumn(name = "user_id", nullable = false)
   private User user;

   @Size(min=3, max = 100)
   private String title;

   @Size(min=3, max = 50)
   private String staff;

   private Long degree;

   public Employee() {}

   public Employee( String title, String staff, Long degree) {
       super();
       this.title = title;
       this.staff = staff;
       this.degree = degree;
   }
   
   public Integer getId() {
       return id;
   }

   public void setId(Integer id) {
       this.id = id;
   }

   public String getTitle() {
       return title;
   }

   public void setTitle(String title) {
       this.title = title;
   }

   public String getStaff() {
       return staff;
   }

   public void setStaff(String staff) {
       this.staff = staff;
   }

   public Long getDegree() {
       return degree;
   }

   public void setDegree(Long degree) {
       this.degree = degree;
   }

   public User getUser() {
       return user;
   }

   public void setUser(User user) {
       this.user = user;
   }

}

EmployeeRepository.java

public interface EmployeeRepository extends CrudRepository<Employee, Integer>{
   Optional<Employee> findById(Long id);
}

谢谢您的帮助！

Answer 1

您需要确保您的身体类型Assignment具有类似属性

public class Assignment {
    public Long employee_id;
    // ommitted
}

并通过您的方法获取它

@PostMapping("/add")
public void addEmployee(@PathVariable(value = "employee_id", required = false) Long employee_id, @RequestBody Assignment a) {
    Long employee_id = a.employee_id;
    Employee employeeById = employeeRepository.findById(employee_id)
        .orElseThrow(() -> new RuntimeException("Employee not found"));
    a.setEmployee(employeeById);
    assignmentRepository.addAssignment(a);
}

但是这种实现不符合HTTP标准。请考虑您的实际实现几乎遵守这些标准，因此您应该以以下方式重命名API：POST URL/v1/employees/{employee_id}
blog解释了这些标准

编辑并提供了规范：

@PostMapping(values = {"/v1/employees", "/v1/employees/{employee_id}"})
public void addEmployee(@PathVariable(value = "employee_id", required = false) Long employee_id, @RequestBody Assignment a) {
    Long yourId = employee_id != null ? employee_id : a.employee_id;
    if (yourId == null) {
        throw new RuntimeException("No id given"); // Not clean either but implemented by OP
    } else {
        Employee employeeById = employeeRepository.findById(yourId)
            .orElseThrow(() -> new RuntimeException("Employee not found"));
        a.setEmployee(employeeById);
        assignmentRepository.addAssignment(a);
    }
}

由于pathvariable是可选的，因此您尝试首先从url获取它，然后再从您的body对象获取它。

编辑2：可能没有员工编号创建Assignment
第一种情况：您接受一个工作分配可能没有雇员。
只需将您的关系从“分配”更改为“雇员”：

    @OneToOne(optional = true)
    @JoinColumn(name = "employee_id", nullable = true)
    private Employee employee;

第二种情况：您想先创建一个新的Employee，然后将其绑定到您的分配，因为Assignment应该始终有一个Employee

@PostMapping(values = {"/v1/employees", "/v1/employees/{employee_id}"})
public void addEmployee(@PathVariable(value = "employee_id", required = false) Long employee_id, @RequestBody Assignment a) {
    Long yourId = employee_id != null ? employee_id : a.employee_id;
    Employee employeeById = yourId != null ?
        employeeRepository.findById(yourId).orElseThrow(() -> new RuntimeException("Employee not found"))
        : new Employee("title","staff",2L);
    a.setEmployee(employeeById);
    assignmentRepository.addAssignment(a);
}

@PostMapping与多个RequestBody

1 个答案: