在Room Kotlin中插入改造响应

时间:2020-09-14 10:16:20

标签: android kotlin retrofit

我试图在数组列表中插入response.body(),但是它为空。这个想法是将数据从服务器发送到数据库。我可以毫无问题地在recyclerview中显示它,但是不知道如何在本地存储所有数据。

代码在这里:

    val service = client!!.create(ApiInterface::class.java)
    val call = service.pOIs
    call!!.enqueue(object : Callback<PoiResponse?> {
        override fun onResponse(call: Call<PoiResponse?>, response: Response<PoiResponse?>) {
            if (response.isSuccessful) {
                
                val result = response.body()
                //here i send the response to a poi model to show it in a recyclerview, works fine
                val poiList: ArrayList<Poi>? = result?.list
                
                //same data, but for persistence
                val poiRoomList: ArrayList<PoiRoom>? = result?.roomList //here is getting null

                onFinishedListener!!.onFinished(poiList, poiRoomList)

响应:

class PoiResponse {
    var list: ArrayList<Poi>? = null
    var roomList: ArrayList<PoiRoom>? = null
}

道:

@Dao
interface PoiDao {

   @Insert(onConflict = OnConflictStrategy.IGNORE)
   fun insert(poiRoom: PoiRoom)

   @Insert(onConflict = REPLACE)
   fun insertAllPois(poisRoomList: List<PoiRoom>?);


   @Query("SELECT * FROM poi_table")
   fun getAllPois(): LiveData<List<PoiRoom>>
   
}

实体:

@Entity(tableName = "poi_table")
class PoiRoom(
        @PrimaryKey(autoGenerate = true)
        var id: Int = 0,
        @ColumnInfo(name = "title")
        val title: String,
        @ColumnInfo(name = "address")
        val address: String,
        @ColumnInfo(name = "transport")
        val transport: String,
        @ColumnInfo(name = "email")
        val email: String,
        @ColumnInfo(name = "geocoordinates")
        val geocoordinates: String,
        @ColumnInfo(name = "description")
        val description: String)
       

Json回应,一个兴趣点列表:

{
  "list": [
    {
      "id": "1",
      "title": "Casa Batlló",
      "geocoordinates": "41.391926,2.165208"
    },
    {
      "id": "2",
      "title": "Fundació Antoni Tàpies",
      "geocoordinates": "41.39154,2.163835"
    },

数据库类:

@Database(entities = [PoiRoom::class], version = 1)
abstract class PoiRoomDatabase : RoomDatabase() {

    abstract fun poiDao(): PoiDao

    companion object {
        @Volatile
        private var INSTANCE: PoiRoomDatabase? = null

        fun getDatabase(
                context: Context,
                scope: CoroutineScope
        ): PoiRoomDatabase {
            return INSTANCE ?: synchronized(this) {
                val instance = Room.databaseBuilder(
                        context.applicationContext,
                        PoiRoomDatabase::class.java,
                        "poi_database"
                )
                        .fallbackToDestructiveMigration()
                        .build()
                INSTANCE = instance
                instance
            }
        }

    }
}

解决方案:

1º)从响应中删除数组列表

2º)用这样的政治家映射房间清单:

  val mappedRoomList =   poiList?.map { PoiRoom(it.id, it.title, it.address, it.transport, it.email, it.geocoordinates, it.description) }

3º)创建了将映射列表添加到roomdatabase的方法:

override fun sendDataToRoomDataBase(poiOfflineList: List<PoiRoom?>?) {

     poiDao?.insertAllPois(poiOfflineList)

    }

4º)创建了转换器:

class PoiConverters {
  
        private val gson = Gson()

        @TypeConverter
        fun stringToListPoi(data: String?): List<Poi?>? {
            if (data == null) {
                return Collections.emptyList()
            }
            val listType: Type = object :
                    TypeToken<List<Poi?>?>() {}.type

            return gson.fromJson<List<Poi?>>(data, listType)
        }

        @TypeConverter
        fun listPoiToString(list: List<Poi?>?): String? {
            return gson.toJson(list)
        }
}

多数民众赞成在:)

1 个答案:

答案 0 :(得分:1)

据我所知,请检查您的Json响应:那里只有“列表”键,没有“ roomList”键。这意味着,当您解析响应Json并将其插入ArrayList时,您只会“填充”列表类型的对象,而不是“ roomList”,因为它不存在! 我要做的是映射您的响应列表,并使用map函数将其映射到RoomList对象。 尝试这样的事情:

override suspend fun insertAllPoiIntoDb(poiList: List<Poi>) {
   yourDatabase.yourDao().insertAllObjectsFunction(
     poiList.map {
       it.toRoomObject()
     }
  )
}

toRoomObject()函数表示Poi对象中的某些函数逻辑,该函数将Poi转换为RoomPoi(即对象的构造)。