最好的方法是什么?例如:
当用户在qx.fx.effect.core.Fade(DOM)
按钮上显示时,我希望窗口淡出(minimize
)。所以我在窗口类中做了这个:
this.addListener("appear", function() {
this.minimizeEffect = /*fade effect*/;
},this);
this.addListener("beforeMinimize", function() {
this.minimizeEffect.start();/*delay(1000);*/
},this);
我需要做延迟,因为(我认为)否则窗口会在刚开始褪色时最小化!
有解决方案吗我甚至尝试了finish
事件的效果而没有运气。
谢谢!
编辑:
我的delay()
函数错了..所以它不会“编译”,这让我更加困惑:
function delay(ms){//this works (it fades ok)
var date = new Date();
var curDate = new Date();
while(curDate-date < milis)//this is wrong, milis don't exist
curDate = new Date();
}
function delay(ms){//it donesn't work (no fade)
var date = new Date();
var curDate = new Date();
while(curDate-date < ms)//this is "good"
curDate = new Date();
}
答案 0 :(得分:4)
我建议以下
var win = new qx.ui.window.Window("First Window").set({
width: 300,
height: 300,
opacity: 0,
showMinimize: false
});
var hideEffect;
win.addListenerOnce('appear',function(){
var el = win.getContainerElement().getDomElement();
var showEffect = new qx.fx.effect.core.Fade(el).set({
from: 0, to: 1 });
hideEffect = new qx.fx.effect.core.Fade(el).set({
from: 1, to: 0 });
hideEffect.addListener('finish',function(e){
win.setOpacity(0);
win.close();
});
showEffect.addListener('finish',function(){
win.setOpacity(1);
});
showEffect.addListenerOnce('finish',function(){
win.addListener('appear',function(){
showEffect.start();
});
});
showEffect.start();
});
win.addListener('beforeClose',function(){
if (win.getOpacity() == 1){
hideEffect.start();
e.stopPropagation();
}
});
this.getRoot().add(win, {left:10, top:30});
var openBtn = new qx.ui.form.Button('Open Window');
openBtn.addListener('execute',function(){win.open();});
this.getRoot().add(openBtn, {left:10, top:10});
在qooxdoo游乐场中运行此操作