Question

我正在尝试使用UART接收9个浮点数据，每个浮点都以XXX.XX的形式发送。因此，我将收到5 * 9 = 45的信息。

我尝试将数据接收到45个字符的数组中，然后可以使用该数组进行操作，但是在运行应用程序时出现此著名错误：分段错误（核心已转储 >）

我的代码是

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <stdio.h>
#include <string>
#include <string.h>
#include <errno.h>
#include <wiringSerial.h>
using namespace std;
int main (){
    int fd;
    float courant;
    float voltage;
    float activepower;
    float reactivepower;
    float apparentpower;
    float powerfactor;
    float frequency;
    float temperature;
    float indexIns;
    string courantC;
    string voltageC;
    string activepowerC;
    string reactivepowerC;
    string apparentpowerC;
    string powerfactorC;
    string frequencyC;
    string temperatureC;
    string indexinsC;

    char receivedData[45];
    int i=0;
    if ((fd = serialOpen("/dev/ttyS1",9600)) < 0)
    {
        fprintf(stderr,"Unable to open serial device %s\n",strerror(errno));
        return 1;
    }
    // Loop , getting and printing characters

    for (int j=0; j<45; j++)
    {
        i = serialGetchar(fd);
        receivedData[j] = char(i);

        if (j = 44) {
            j = 0;

            courantC = receivedData[0]+receivedData[1]+receivedData[2]+"." + receivedData[3]+receivedData[4];
            voltageC = receivedData[5]+receivedData[6]+receivedData[7]+"." + receivedData[8]+receivedData[9];
            activepowerC = receivedData[10]+receivedData[11]+receivedData[12]+"." + receivedData[13]+receivedData[14];
            reactivepowerC = receivedData[15]+receivedData[16]+receivedData[17]+"." + receivedData[18]+receivedData[19];
            apparentpowerC = receivedData[20]+receivedData[21]+receivedData[22]+"." + receivedData[23]+receivedData[24];
            powerfactorC = receivedData[25]+receivedData[26]+receivedData[27]+"." + receivedData[28]+receivedData[29];
            frequencyC = receivedData[30]+receivedData[31]+receivedData[32]+"." + receivedData[33]+receivedData[34];
            temperatureC = receivedData[35]+receivedData[36]+receivedData[37]+"." + receivedData[38]+receivedData[39];
            indexinsC = receivedData[40]+receivedData[41]+receivedData[42]+"." + receivedData[43]+receivedData[44];

           
        }
        printf("a=%c ", char(i));

        fflush(stdout);

用于编译的命令

gcc receiveData.cpp -o receiveData -lwiringPi -lpthread -lstdc++

Answer 1

此行：

courantC = receivedData[0]+receivedData[1]+receivedData[2]+"." + receivedData[3]+receivedData[4];

导致未定义的行为（UB），可能是段故障的原因。在这一行中，您有一个char数组，这里是"."，带有2个字符，'.'和'\0'。该数组存储在某处。当您像这样使用它时，它会衰减为指向数组开头的指针。其余全部为char，它们都是C中的整数。它们被加在一起并添加到指向数组"."的指针中。然后，该指针指向String类访问的某个未知内存区域，以将其复制到courantC。但是访问该区域会导致UB。

分段故障（核心已转储）

1 个答案: