Question

我有3张桌子：

thalagalage@3n1gm4:~/chamika/Python/DjangoBlog$ ll
total 16
drwxr-xr-x  4 thalagalage thalagalage 4096 sept.  5 19:02 ./
drwxrwxr-x 11 thalagalage thalagalage 4096 sept.  5 18:13 ../
drwxr-xr-x  3 thalagalage thalagalage 4096 sept.  5 19:32 django_blog/
drwxr-xr-x  4 thalagalage thalagalage 4096 sept.  5 18:03 django_env/
thalagalage@3n1gm4:~/chamika/Python/DjangoBlog$ source django_env/bin/activate
(django_env) thalagalage@3n1gm4:~/chamika/Python/DjangoBlog$ python3 -m django --version
3.1.1
(django_env) thalagalage@3n1gm4:~/chamika/Python/DjangoBlog$ cd django_blog
(django_env) thalagalage@3n1gm4:~/chamika/Python/DjangoBlog/django_blog$ ll
total 32
drwxr-xr-x 3 thalagalage thalagalage  4096 sept.  5 19:32 ./
drwxr-xr-x 4 thalagalage thalagalage  4096 sept.  5 19:02 ../
drwxr-xr-x 3 thalagalage thalagalage  4096 sept.  6 01:02 django_blog/
(django_env) thalagalage@3n1gm4:~/chamika/Python/DjangoBlog/django_blog$ python3 manage.py runserver

<?php
if (isset($_POST['submit'])) {
    $first_name = $_POST["first_name"];
    $last_name = $_POST['last_name'];
    $phone_number = $_POST['phone_number'];
    $date_end = $_POST['contract_end'];
    $email_address = $_POST['email_address'];
    $date = new DateTime($date_end);
    $now = new DateTime();
    $contract_copy = $_POST['file1'];
    $submit_button = $_POST['submit'];
}

echo $first_name;
?>

和

grailsVersion=4.0.1
gorm.version=7.0.2.RELEASE

表

pet:
id | ...

vaccination:
id | petId | ...

visit:
id | petId | ...

中的

是外键。

当我尝试制作vaccination时遇到错误

visit

或

petId

错误是：

join

我了解这是由外键生成的某种“虚拟”列。但是我不知道该如何加入。感谢帮助！附言该表是由typeorm生成的

Answer 1

列，方案和表名区分大小写，并且当您没有引号时，PostgreSQL使用所键入内容的小写版本。

因此，请使用“ petId”，请访问。“ petId”和疫苗接种。“ petId”，以防止出现意外情况。

您甚至可以决定始终将列名，方案名和表名都用引号引起来，那么您就不会对此感到困惑。例如“疫苗接种”。“ petId”

psql外键和联接表

1 个答案: