我有三张桌子:
estate_field_data
estate_field_types
estate_fields
我在浏览器中输入的唯一内容是estate_field_types.ID = 3
estate_fields
包含estate_field_types.ID => estate_fields.FieldType
但estate_field_data
没有estate_field_types.ID
的定义,而是estate_field_data.FieldID => estate_fields.ID
如何使用此单个值从所有三行中删除?
谢谢! : - )
答案 0 :(得分:3)
您必须将其作为3个单独的语句(除非您在外键引用上设置了级联删除)。我假设estate_fields
中有一个PK(我选择称之为estate_field_id
)estate_field_data
引用(否则,我不确定我们如何确定从该表中删除的内容)
delete from estate_field_data where estate_field_id in (select estate_field_id from estate_fields where FieldType = 3)
delete from estate_fields where FieldType = 3
delete from estate_field_types where ID = 3
答案 1 :(得分:-1)
尝试使用连接.... 达米恩......我们应该为联盟使用建议OP吗?在OP情况下可能会更快?
Delete K From estate_field_data K
Inner Join estate_fields F on F.estate_field_id = K.estate_field_id
Where F.estate_field_id = 3