我不久前就开始学习Python,并且我正在尝试为列表做递归函数。这是功能:
def get_employee(j, field, value):
res = j
for x in res:
if x['Name'] == field and x['Value'] == value:
return res
elif "Properties" not in x:
if x is not None:
continue
elif "Properties" in x:
return get_employee(x['Properties'], field, value)
这是我的JSON:
[{
"Value": "Sales",
"Name": "Department",
"Properties": [{
"Value": "US",
"Name": "Country",
"Properties": [{
"Value": "Employee",
"Name": "EmployeeType",
"Properties": [{
"Value": "Manya Bishter",
"Name": "EmployeeFullName",
"Properties": [{
"Value": 1111,
"Name": "EmployeeID"
},
{
"Value": "Manya",
"Name": "EmployeeFirstName"
},
{
"Value": "Bishter",
"Name": "EmployeeLastName"
}
]
},
{
"Value": "Michael Ort",
"Name": "EmployeeFullName",
"Properties": [{
"Value": 1112,
"Name": "EmployeeID"
},
{
"Value": "Michael",
"Name": "EmployeeFirstName"
},
{
"Value": "Ort",
"Name": "EmployeeLastName"
}
]
}
]
},
{
"Value": "Manager",
"Name": "EmployeeType",
"Properties": [{
"Value": "Nick Fair",
"Name": "EmployeeFullName",
"Properties": [{
"Value": 1113,
"Name": "EmployeeID"
},
{
"Value": "Nick",
"Name": "EmployeeFirstName"
},
{
"Value": "Fair",
"Name": "EmployeeLastName"
}
]
}]
}
]
}]
},
{
"Value": "Marketing",
"Name": "Department",
"Properties": [{
"Value": "US",
"Name": "Country",
"Properties": [{
"Value": "Employee",
"Name": "EmployeeType",
"Properties": [{
"Value": "Tamta Hiresh",
"Name": "EmployeeFullName",
"Properties": [{
"Value": 1121,
"Name": "EmployeeID"
},
{
"Value": "Tamta",
"Name": "EmployeeFirstName"
},
{
"Value": "Hiresh",
"Name": "EmployeeLastName"
}
]
}]
}]
}]
}
]
该功能仅在Manya上有效,而在其他地方则无效。
例如,如果我这样做:
print(get_employee(myjson, "EmployeeFirstName", "Nick"))
它将打印:
[{'Value': 1111, 'Name': 'EmployeeID'}, {'Value': 'Manya', 'Name': 'EmployeeFirstName'}, {'Value': 'Bishter', 'Name': 'EmployeeLastName'}]
但是对于其他人(例如Nick
),它将返回None
。
可以帮忙吗?
谢谢!
答案 0 :(得分:0)
代码如下:
Deconstruct
您的递归函数的问题是,一旦到达def get_employee(data, field, value):
result = []
def recursor(j, field, value):
res = j
for x in res:
if x['Name'] == field and x['Value'] == value:
result.append(res)
elif "Properties" not in x:
if x is not None:
continue
elif "Properties" in x:
recursor(x['Properties'], field, value)
recursor(data,field,value)
return result
;它将停止外部for循环return get_employee(x['Properties'], field, value)
。因此,它将永远不会在列表中的下一项上运行。