Question

在编组对象树时，我正在使用@XmlJavaTypeAdapter。某些适配器返回自身具有@XmlJavaTypeAdapter注释的类的对象。当我使用与websphere 7打包的JAXB实现时，这很好用，但是当我使用org.eclipse.persistence.jaxb.JAXBContextFactory时，忽略第一个适配器返回的对象上的@XmlJavaTypeAdapter注释。这是一个已知问题，还是我做错了什么？

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Root.class,C.class);

        System.out.println(jc.getClass());

        Root root = new Root();
        A a = new A();
        root.a = a;

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(root, System.out);
    }

}

根

@XmlRootElement
public class Root {

   @XmlJavaTypeAdapter(AAdapter.class)
   public A a;

}

A

public class A {

   public B b = new B();

}

乙

public class B {

  @XmlJavaTypeAdapter(GAdapter.class)
  @XmlElement(name="b")
  public G<C> gc = new G<C>();

  public B(){
    gc.t = new C();
  }
}

C

public class C {

    public String c = "Foo";

}

public class G<T> {

  T t;

}

然后适用于A ...

public class AAdapter extends XmlAdapter<B, A> {

    @Override
    public A unmarshal(B b) throws Exception {

        A a = new A();
        a.b = b;

        return a;
    }

    @Override
    public B marshal(A a) throws Exception {

        return a.b;
    }

}

适用于泛型类型的适配器

public class GAdapter<T> extends XmlAdapter<T, G<T>> {

  @Override
  public G<T> unmarshal(T c) throws Exception {

    return new G<T>();
  }

  @Override
  public T marshal(G<T> g) throws Exception {

    return g.t;
  }

}

在编组课程com.sun.xml.bind.v2.runtime.JAXBContextImpl

时

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>

<root>

    <a>

    <b xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="c">

        <c>Foo</c>

    </b>

    </a>

</root>

与org.eclipse.persistence.jaxb.JAXBContext编组时

<?xml version="1.0" encoding="UTF-8"?>

<root>

   <a>

      <b>forum237.C@23752375</b>

   </a>

</root>

我认为问题在于泛型类型。目标是跳过封送的泛型类型，并且只封送T，以及处理T的注释（如果有的话）。

Answer 1

注意：我是EclipseLink JAXB (MOXy)领导。

我能够重新创建此问题并确认这是一个错误（https://bugs.eclipse.org/350626）。

<强>根

package example;

import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;

@XmlRootElement
public class Root {

    @XmlJavaTypeAdapter(AAdapter.class)
    public A<B> a;

}

<强> A

package example;

public class A<T> {

    public T t;

}

<强> AAdapter

package example;

import javax.xml.bind.annotation.adapters.XmlAdapter;

public class AAdapter<T> extends XmlAdapter<T, A<T>> {

    @Override
    public A<T> unmarshal(T v) throws Exception {
        return new A<T>();
    }

    @Override
    public T marshal(A<T> v) throws Exception {
        return v.t;
    }

}

<强>乙

package example;

public class B {

}

<强>演示

package example;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Root.class, B.class);

        Root root = new Root();
        A<B> a = new A<B>();
        a.t = new B();
        root.a = a;

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(root, System.out);
    }

}

<强>输出

<?xml version="1.0" encoding="UTF-8"?>
<root>
   <a>example.B@3ecfff</a>
</root>

预期输出

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <a xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="b"/>
</root>

嵌套的@XmlJavaTypeAdapter注释被忽略，其中嵌套对象在使用eclispelink时是通用的

根

A

乙

C

1 个答案: