有条件的groupby上的熊猫增量值

Question

让我们说我有这样的df，需要对链接进行分组， 如果链接重复3次以上，则应增加其值

name    links
A   https://a.com/-pg0
B   https://b.com/-pg0
C   https://c.com/-pg0
D   https://c.com/-pg0
x   https://c.com/-pg0
y   https://c.com/-pg0
z   https://c.com/-pg0
E   https://e.com/-pg0
F   https://e.com/-pg0

预期的输出，这里的名称为C，D，x，y，z，重复3个以上，因此前3个将为零，下一个将递增

name    links
A   https://a.com/-pg0
B   https://b.com/-pg0
C   https://c.com/-pg0
D   https://c.com/-pg0
x   https://c.com/-pg0
y   https://c.com/-pg1
z   https://c.com/-pg1
E   https://e.com/-pg0
F   https://e.com/-pg0

Answer 1

您可以尝试将cumcount与//

s = df.groupby('links').cumcount()//3
Out[125]: 
0    0
1    0
2    0
3    0
4    0
5    1
6    1
7    0
8    0
dtype: int64

df['links'] = df['links'] + s.astype(str)