Question

我来自iphone开发，你不能在后台发送短信而不要求用户确认发送。可以在android的后台发送短信，这样就不需要用户干预了吗？

Answer 1

发送带有短信发送通知的短信吐司。

方法调用如下。

sendSMS("98********","This is test message");

方法签名如下。

/*
 * BroadcastReceiver mBrSend; BroadcastReceiver mBrReceive;
 */
private void sendSMS(String phoneNumber, String message) {
    ArrayList<PendingIntent> sentPendingIntents = new ArrayList<PendingIntent>();
    ArrayList<PendingIntent> deliveredPendingIntents = new ArrayList<PendingIntent>();
    PendingIntent sentPI = PendingIntent.getBroadcast(mContext, 0,
            new Intent(mContext, SmsSentReceiver.class), 0);
    PendingIntent deliveredPI = PendingIntent.getBroadcast(mContext, 0,
            new Intent(mContext, SmsDeliveredReceiver.class), 0);
    try {
        SmsManager sms = SmsManager.getDefault();
        ArrayList<String> mSMSMessage = sms.divideMessage(message);
        for (int i = 0; i < mSMSMessage.size(); i++) {
            sentPendingIntents.add(i, sentPI);
            deliveredPendingIntents.add(i, deliveredPI);
        }
        sms.sendMultipartTextMessage(phoneNumber, null, mSMSMessage,
                sentPendingIntents, deliveredPendingIntents);

    } catch (Exception e) {

        e.printStackTrace();
        Toast.makeText(getBaseContext(), "SMS sending failed...",Toast.LENGTH_SHORT).show();
    }

}

现在还有两个类SmsDeliveredReceiver，SmsSentReceiver如下所示。

public class SmsDeliveredReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent arg1) {
    switch (getResultCode()) {
    case Activity.RESULT_OK:
        Toast.makeText(context, "SMS delivered", Toast.LENGTH_SHORT).show();
        break;
    case Activity.RESULT_CANCELED:
        Toast.makeText(context, "SMS not delivered", Toast.LENGTH_SHORT).show();
        break;
    }
}

}

现在发送SMSSentReceiver。

public class SmsSentReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent arg1) {
    switch (getResultCode()) {
    case Activity.RESULT_OK:
        Toast.makeText(context, "SMS Sent", Toast.LENGTH_SHORT).show();

        break;
    case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
        Toast.makeText(context, "SMS generic failure", Toast.LENGTH_SHORT)
                .show();

        break;
    case SmsManager.RESULT_ERROR_NO_SERVICE:
        Toast.makeText(context, "SMS no service", Toast.LENGTH_SHORT)
                .show();

        break;
    case SmsManager.RESULT_ERROR_NULL_PDU:
        Toast.makeText(context, "SMS null PDU", Toast.LENGTH_SHORT).show();
        break;
    case SmsManager.RESULT_ERROR_RADIO_OFF:
        Toast.makeText(context, "SMS radio off", Toast.LENGTH_SHORT).show();
        break;
    }
}

}

现在权限打开你的AndroidManifest.xml并添加到下面的行

<uses-permission android:name="android.permission.SEND_SMS"/>

及其完成.......

Answer 2

是的，你也可以。

SmsManager sm = SmsManager.getDefault(); 
sm.sendTextMessage(number, null, message, null, null);

Answer 3

见http://thinkandroid.wordpress.com/2010/01/08/sending-sms-from-application/。您需要适当的权限。

Answer 4

最佳答案很好，但在API级别23以上，您需要务实地获得许可。否则每次都会提示权限。

 private static final int PERMISSION_REQUEST_CODE = 1;

if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.M) {

    if (checkSelfPermission(Manifest.permission.SEND_SMS)
            == PackageManager.PERMISSION_DENIED) {

        Log.d("permission", "permission denied to SEND_SMS - requesting it");
        String[] permissions = {Manifest.permission.SEND_SMS};

        requestPermissions(permissions, PERMISSION_REQUEST_CODE);

    }
}

如何使用Android在BACKGROUND中发送短信？

4 个答案: