Question

我正在尝试将多个词典的列表保存在一个pickle文件中，并且可以随时在列表中存储一个新的附加词典，并将其保存在pickle文件中，然后将pickle文件作为词典列表加载。到目前为止，代码的行为如下：

我第一次尝试在列表中添加字典时，泡菜文件如下所示（数据已成功保存）：

Running info()......

===================================================
Existing data: []
===================================================

Running save_score()......

Inside try: {}
============================================
Existing data: [{}]
New data: {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}
Saved Data: [{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}]
===================================================

第二次尝试在列表中添加字典时，泡菜文件如下：

Running info()......

===================================================
Existing data: [[{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}]]
===================================================

Running save_score()......

Inside try: [{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}]
============================================
Existing data: [[{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}], [{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}]]
New data: {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}
Saved Data: [[{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}], [{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}], {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}]
===================================================

如您所见（在上面的示例中，字典中的值不是问题），而不是附加到现有列表，每次都会在列表中创建一个新列表。到目前为止，我还没有解决这个问题并获得预期的输出。

预期输出应为：

Saved Data: [{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}, {}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}]

相反，输出为：

Saved Data: [[{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}], [{}, {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}], {'ComputerName': 'computer name', 'PlayerName': 'user 1', 'ComputerScore': 3, 'PlayerScore': 1}]

代码如下：

import pickle

data = []
computer_name = "computer name"
username = "user 1"
computer_score = 3
human_score = 1

def save_score():
    try:
        existing_data = pickle.load(open("w6_project.p", "rb"))
        print("Inside try: {}".format(existing_data))
        data.append(existing_data)
    except (OSError, IOError) as e:
        pickle.dump({}, open("w6_project.p", "wb"))
    new_data = {"ComputerName": computer_name, "PlayerName": username, "ComputerScore": computer_score, "PlayerScore": human_score}
    print("============================================")
    print("Existing data: {}".format(data))
    data.append(new_data)
    print("New data: {}".format(new_data))
    pickle.dump(data, open("w6_project.p", "wb"))  # Save the data into a pickle file
    print("Saved Data: {}".format(data))
    print("===================================================")
    pass

def info():
    try:
        existing_data = pickle.load(open("w6_project.p", "rb"))
        data.append(existing_data)
    except (OSError, IOError) as e:
        pickle.dump({}, open("w6_project.p", "wb"))
    print("===================================================")
    print("Existing data: {}".format(data))
    print("===================================================")
    pass

def main():
    print("Running info()......\n")
    info()
    print("\nRunning save_score()......\n")
    save_score()

if __name__ == "__main__":
    main()

Answer 1

问题是您有两个列表-data和existing_data-并且您以错误的方式加入了它们。使用append()可以将一个列表放在另一个列表中。您应该使用extend()来加入他们

 data.extend(existing_data)

或更短

 data += existing_data

但是，如果您在加载泡菜后添加新数据，则应该直接将其直接关联到变量

 data = pickle.load(...)

编辑：最小的工作示例

import pickle

computer_name = "computer name"
username = "user 1"
computer_score = 3
human_score = 1

def save_score():
    
    try:
        data = pickle.load(open("w6_project.p", "rb"))
        print("Inside try: {}".format(data))
    except (OSError, IOError) as e:
        data = []
        
    new_data = {"ComputerName": computer_name, "PlayerName": username, "ComputerScore": computer_score, "PlayerScore": human_score}
    data.append(new_data)

    pickle.dump(data, open("w6_project.p", "wb"))  # Save the data into a pickle file

    print("============================================")
    print("Existing Data: {}".format(data))
    print("New Data: {}".format(new_data))
    print("Saved Data: {}".format(data))
    print("Length Data: {}".format( len(data) ))
    print("===================================================")

def info():
    try:
        data = pickle.load(open("w6_project.p", "rb"))
    except (OSError, IOError) as e:
        data = []
        
    print("===================================================")
    print("Existing Data: {}".format(data))
    print("Length Data: {}".format( len(data) ))
    print("===================================================")

def main():
    print("Running info()......\n")
    info()

    print("\nRunning save_score()......\n")
    save_score()

if __name__ == "__main__":
    main()

泡菜-无法正确将追加的字典存储到列表中

1 个答案: