猫鼬：属性“拉”在类型“地址[]”上不存在

Question

我在使用Mongoose 5.10.0时遇到困难

请考虑以下课程

帐户：

export class Account {
    _id: string;
    email: string;
    password: string;
    phone: string;
    address?: Address[] = [];
}

地址：

export class Address {
    _id: string;
    streetName: string;
    zipCode: string;
    city: string;
    default: boolean | undefined;
}

以及适当的数据库模型

帐户：

import mongoose, { Schema, Document } from "mongoose";
import { Account } from "../classes/account.class";
import { addressSchema } from "./address.model";

export const accountSchema = new Schema({
    _id: Schema.Types.ObjectId,
    email: String,
    phone: String,
    password: String,
    address: [addressSchema],
);

export type AccountModel = Document & Account;
export const Accounts = mongoose.model<AccountModel>("Account", accountSchema);

地址：

import mongoose, { Schema, Document } from "mongoose";
import { Address } from "../classes/address.class";

export const addressSchema: Schema = new Schema({
    _id: Schema.Types.ObjectId,
    streetName: String,
    zipCode: String,
    city: String,
    default: Boolean,
});

export type AddressModel = Document & Address;
export const Addresses = mongoose.model<AddressModel>("Address", addressSchema);

现在，当我从数据库获得一个帐户并尝试对结果的地址进行提取时，根本找不到pull()-方法，我得到了Property 'pull' does not exist on type 'Address[]'.

定义模式的方式是否存在根本性的错误？我要去哪里错了？

Answer 1

在您的代码中，您期望MongoDB的pull运算符是JavaScript方法。您可以通过两种方法来实现自己的目标：

您可以使用.findOne()检索文档，使用JS代码修改数组（例如slice），然后运行.save()将这些更改与数据库同步。

但是，如果只想提取地址，则可以直接在数据库上运行更新操作：

await Accounts.update({_id: idToFind}, {"$pull": { "address": { _id: addressId } } })

使用第二种方法时，您将只能进行一次数据库调用

Answer 2

import { Types } from "mongoose";
import { AddressModel } from './Address';

const account = await Accounts.findOne({_id: idToFind});
const accountAddressArray = account.address as Types.DocumentArray<AddressModel>
accountAddress.pull(...)