Question

我正在执行此更新查询：

await this.userRepository.query(
    `
        update "user" u
        set profile_pic = i.name
        from user_images_image uii
        inner join image i on uii."imageId" = i."id"
        where uii."userId" = u.id and u.id = ${userId} and i.id = ${imageId};
    `,
);

即使我在数据库客户端中执行相同的查询并且它按预期运行，它也不会终止。

Answer 1

在进行故障排除会话后，我们发现查询已被锁定，因为另一个连接正试图更新相关资源（users表中的记录，其中包含来自user_images_image的外键）以相同的方法处理不同的事务，都等待其结果提交。

通过使用相同的连接，我们最终获得了正确的行为。

我们通过使用锁定监视查询from the docs发现了这一点：

SELECT blocked_locks.pid     AS blocked_pid,
         blocked_activity.usename  AS blocked_user,
         blocking_locks.pid     AS blocking_pid,
         blocking_activity.usename AS blocking_user,
         blocked_activity.query    AS blocked_statement,
         blocking_activity.query   AS current_statement_in_blocking_process,
         blocked_activity.application_name AS blocked_application,
         blocking_activity.application_name AS blocking_application
   FROM  pg_catalog.pg_locks         blocked_locks
    JOIN pg_catalog.pg_stat_activity blocked_activity  ON blocked_activity.pid = blocked_locks.pid
    JOIN pg_catalog.pg_locks         blocking_locks 
        ON blocking_locks.locktype = blocked_locks.locktype
        AND blocking_locks.DATABASE IS NOT DISTINCT FROM blocked_locks.DATABASE
        AND blocking_locks.relation IS NOT DISTINCT FROM blocked_locks.relation
        AND blocking_locks.page IS NOT DISTINCT FROM blocked_locks.page
        AND blocking_locks.tuple IS NOT DISTINCT FROM blocked_locks.tuple
        AND blocking_locks.virtualxid IS NOT DISTINCT FROM blocked_locks.virtualxid
        AND blocking_locks.transactionid IS NOT DISTINCT FROM blocked_locks.transactionid
        AND blocking_locks.classid IS NOT DISTINCT FROM blocked_locks.classid
        AND blocking_locks.objid IS NOT DISTINCT FROM blocked_locks.objid
        AND blocking_locks.objsubid IS NOT DISTINCT FROM blocked_locks.objsubid
        AND blocking_locks.pid != blocked_locks.pid
 
    JOIN pg_catalog.pg_stat_activity blocking_activity ON blocking_activity.pid = blocking_locks.pid
   WHERE NOT blocked_locks.GRANTED;

使用TypeOrm执行时，原始PostgreSQL查询挂起

1 个答案: