例如,我有这个数组:
$bills = array(
array("bill_id"=>"1", "product_id"=>"1", "total"=>"10"),
array("bill_id"=>"2", "product_id"=>"2", "total"=>"20"),
array("bill_id"=>"3", "product_id"=>"1", "total"=>"30"),
array("bill_id"=>"4", "product_id"=>"1", "total"=>"40"),
array("bill_id"=>"5", "product_id"=>"2", "total"=>"50")
);
我们需要将每个产品的总数添加到单个数组中,即从上述数组中生成以下数组的最佳快速清理方法是什么:
$products = array(
array("product_id"=>"1", "total"=>"80"),
array("product_id"=>"2", "total"=>"70")
);
答案 0 :(得分:2)
最快的方法是索引数组,类似这样的
$products = array();
foreach ($bills as $bill) {
$key = $bill['product_id'];
if (isset($products[$key])) {
$products[$key]['total'] += $bill['total'];
} else {
$products[$key] = $bill;
}
}
var_dump($products);
输出
array(2) {
[1]=>
array(3) {
["bill_id"]=>
string(1) "1"
["product_id"]=>
string(1) "1"
["total"]=>
int(80)
}
[2]=>
array(3) {
["bill_id"]=>
string(1) "2"
["product_id"]=>
string(1) "2"
["total"]=>
int(70)
}
}
浏览发票清单
foreach($products as $key=>$bill) {
var_dump($bill);
}
答案 1 :(得分:0)
最简单的方法是单遍循环。
$byProduct = [];
foreach($bills as $bill)
{
$key = $bill['product_id'];
if (!isset($byProduct[$key])) {
$byProduct[$key] = [
'product_id' => $key,
'total' => 0
];
}
$byProduct[$key]['total'] += $bill['total'];
}
var_dump($byProduct)
的结果:
array(2) {
[1] =>
array(2) {
'product_id' =>
string(1) "1"
'total' =>
int(80)
}
[2] =>
array(2) {
'product_id' =>
string(1) "2"
'total' =>
int(70)
}
}
另一种方法是使用array_walk
,但在复杂度方面几乎是相同的:
$byProduct = [];
array_walk($bills, function(&$bill) use (&$byProduct) {
$key = $bill['product_id'];
if (!isset($byProduct[$key])) {
$byProduct[$key] = [
'product_id' => $key,
'total' => 0
];
}
$byProduct[$key]['total'] += $bill['total'];
});