Question

我正在尝试在我的开发环境中提供用户上传的媒体文件。

#settings.py
#[...]
import os
SITE_ROOT = os.path.dirname(os.path.realpath(__file__))
MEDIA_ROOT = (os.path.join(SITE_ROOT, 'media/'))
MEDIA_URL = '/media/'
STATIC_URL = '/static/'
STATICFILES_DIRS = (
  os.path.join(SITE_ROOT, 'static/'),
)
#[...]

#url.py
urlpatterns = patterns('',
  #[...]
  url(r'^%s(?P<path>.*)$' % settings.MEDIA_URL[1:], 'django.views.static.serve',
    {'document_root', settings.MEDIA_ROOT}
  ),
  url(r'^%s(?P<path>.*)$' % settings.STATIC_URL[1:], 'django.views.static.serve',
    {'document_root', settings.STATIC_ROOT}
  ),
)

尝试访问像http://127.0.0.1:8000/media/videos/julian_06.flv这样的上传文件，我得到了

/media/videos/julian_06.flv上的ValueError

字典更新序列元素＃0的长度为40; 2是必需的

Answer 1

我建议您尝试按照static hosting in development

的文档进行操作

if settings.DEBUG:
urlpatterns += patterns('django.contrib.staticfiles.views',
    url(r'^media/(?P<path>.*)$', 'serve'),
)

修改

您的词典在:和,之间应该有 'document_root' 而不是 settings.MEDIA_ROOT

urlpatterns = patterns('', url(r'^%s(?P<path>.*)$' % settings.MEDIA_URL[1:], 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT}), )

Django - 服务媒体ValueError

1 个答案: