我如何使用datetime.strptime解析'2020-07-30T20:40:33.1000000Z'

时间:2020-08-17 08:52:35

标签: python datetime

我正在尝试在Python中解析和转换“ 2020-07-30T20:40:33.1000000Z”:

from datetime import datetime

Data = [{'id': 'XXXXXXXXXXXXX', 'number': 3, 'externalId': '0000', 'dateCreated': '2020-07-30T20:40:33.1005865Z', 'dateUpdated': '2020-07-30T20:40:33.36Z'}], 'tags': []}]
for i in Data:
        creationtime= datetime.strptime(i["dateCreated"],"%Y-%m-%dT%H:%M:%S")

错误:

    raise ValueError("unconverted data remains: %s" %
ValueError: unconverted data remains: .1005865Z

我尝试过:

%Y-%m-%dT%H:%M:%S.%fZ

任何人都可以建议我所缺少的正确格式。

1 个答案:

答案 0 :(得分:2)

如果您确实有7个小数秒的小数位,并且不在乎微秒的1/10 ,则可以使用re.subdatetime.fromisoformat

import re
from datetime import datetime 

s = "2020-07-30T20:40:33.1000000Z"
dt = datetime.fromisoformat(re.sub('[0-9]Z', '+00:00', s))

print(dt)
print(repr(dt))
2020-07-30 20:40:33.100000+00:00
datetime.datetime(2020, 7, 30, 20, 40, 33, 100000, tzinfo=datetime.timezone.utc)

...或使用dateutil的解析器:

from dateutil import parser
dt = parser.parse(s)

print(dt)
print(repr(dt))
2020-07-30 20:40:33.100000+00:00
datetime.datetime(2020, 7, 30, 20, 40, 33, 100000, tzinfo=tzutc())

...或者甚至是pandas的to_datetime,如果您仍然可以使用该lib:

import pandas as pd
dt = pd.to_datetime(s)

print(dt)
print(repr(dt))
2020-07-30 20:40:33.100000+00:00
Timestamp('2020-07-30 20:40:33.100000+0000', tz='UTC')

通常不相关(取决于用例),但请注意,便捷性会花费您更多时间:

%timeit datetime.fromisoformat(re.sub('[0-9]Z', '+00:00', s))
1.92 µs ± 151 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

%timeit parser.parse(s)
79.8 µs ± 3.46 µs per loop (mean ± std. dev. of 7 runs, 10000 loops each)

%timeit pd.to_datetime(s)
62.4 µs ± 1.17 µs per loop (mean ± std. dev. of 7 runs, 10000 loops each)