我想实现一个并发对象池,其中返回shared_ptr并且不需要将其显式返回池。我基本上在一个并发队列中为它分配了一个推送shared_ptrs的数组并实现了一个自定义deletor。似乎工作。我错过了什么吗?
#ifndef CONCURRENTOBJECTPOOL_H
#define CONCURRENTOBJECTPOOL_H
#include <boost/shared_ptr.hpp>
#include <boost/shared_array.hpp>
#include <tbb/concurrent_queue.h>
namespace COP
{
template<typename T>
class ConcurrentObjectPool;
namespace
{
template<typename T>
class ConcurrentObjectPoolDeletor
{
public:
ConcurrentObjectPoolDeletor(ConcurrentObjectPool<T>& aConcurrentObjectPool):
_concurrentObjectPool(aConcurrentObjectPool) {}
void operator()(T *p) const;
private:
ConcurrentObjectPool<T>& _concurrentObjectPool;
};
} // Anonymous namespace for ConcurrentObjectPoolDeletor
template <typename T>
class ConcurrentObjectPool
{
public:
ConcurrentObjectPool(const unsigned int aPoolSize)
: _goingDown(false),
_poolSize(aPoolSize),
_pool(new T[_poolSize]),
_ConcurrentObjectPoolDeletor(*this)
{
for(unsigned int i = 0; i < _poolSize; ++i)
{
boost::shared_ptr<T> curr(&_pool[i], _ConcurrentObjectPoolDeletor);
_objectQueue.push(curr);
}
}
boost::shared_ptr<T> loan()
{
boost::shared_ptr<T> curr;
_objectQueue.pop(curr);
return curr;
}
~ConcurrentObjectPool()
{
_goingDown = true;
_objectQueue.clear();
}
private:
void payBack(T * p)
{
if (! _goingDown)
{
boost::shared_ptr<T> curr(p, _ConcurrentObjectPoolDeletor);
_objectQueue.push(curr);
}
}
bool _goingDown;
const unsigned int _poolSize;
const boost::shared_array<T> _pool;
const ConcurrentObjectPoolDeletor<T> _ConcurrentObjectPoolDeletor;
tbb::concurrent_bounded_queue<boost::shared_ptr<T> > _objectQueue;
friend class ConcurrentObjectPoolDeletor<T>;
};
namespace
{
template<typename T>
void ConcurrentObjectPoolDeletor<T>::operator()(T *p) const
{
_concurrentObjectPool.payBack(p);
}
} // Anonymous namespace for ConcurrentObjectPoolDeletor
} // Namespace COP
#endif // CONCURRENTOBJECTPOOL_H
答案 0 :(得分:2)
在_goingDown
的析构函数中设置ConcurrentObjectPool
标志和在payBack()
中读取标志之间存在竞争。它可能导致内存泄漏。
实际上,如果您不尝试使析构函数与payBack()
同时运行,则可能会更好。无论如何,从_goingDown
标志是池对象的一部分这一事实开始并不安全,因此在销毁池之后访问它会导致未定义的行为 - 即所有对象必须在它之前返回到池中破坏。
答案 1 :(得分:0)
看起来不错。您在使用它时遇到任何问题吗?