Question

第34行显然是发生错误的地方，我是pygame的新手，所以我实际上不知道发生了什么。该代码用于在单击图像后执行功能。我也不知道这是否可行，因为此错误使我无法知道。

import pygame


black = (0, 0, 0)
white = (255, 255, 255)
green = (0, 255, 0)
red = (255, 0, 0)
pygame.init()
size = (500, 400)

screen = pygame.display.set_mode(size)
pygame.draw.rect(screen, red,(150,450,100,50))
button1 = pygame.Rect(100,100,50,50)
button2 = pygame.Rect(200,200,50,50)
button3 = pygame.Rect(130,250,50,50)
pygame.display.set_caption("Yami no Game")

txt = pygame.image.load('txt.png')
Stxt = pygame.transform.scale(txt,(48,48))

exe = pygame.image.load('exe.jpg')
Sexe = pygame.transform.scale(exe,(48,48))
done = False
clock = pygame.time.Clock()

background_image=pygame.image.load('windows_background.jpg').convert()
 
while not done:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            done = True
    mouse = pygame.mouse.get_pos()   # position
    click = pygame.mouse.get_pressed()  # left/right click
    if Sexe[100] + Sexe[48] > mouse[0] > Sexe[100] and Sexe[100] + Sexe(48) > mouse[1] > Sexe[100]:  # Mouse coordinates checking.
        if click[0] == 1: # Left click
            import The_Start #ignore this
    
    screen.blit(background_image, [0,0])
    screen.blit(Stxt,[100,100])
    screen.blit(Sexe,[250,250])

    pygame.display.update()
 

    clock.tick(60)
 

pygame.quit()

Answer 1

似乎您想评估鼠标是否位于pygame.Surface对象Sexe所覆盖的矩形区域中。我建议通过pygame.Rect形式Sexe获取一个get_rect()对象。使用collidepoint()检查鼠标是否在矩形区域中。请注意，Surface没有位置，当blit时，它获取一个位置。因此，矩形的位置必须由关键字参数（Sexe.get_rect(topleft = (250,250))）设置：

while not done:
    # [...]

    sexe_rect = Sexe.get_rect(topleft = (250, 250)) # position of Sexe as in blit(Sexe, [250,250])
    mouse_pos = pygame.mouse.get_pos()
    if sexe_rect.collidepoint(mouse_pos):
        click = pygame.mouse.get_pressed()
        if click[0] == 1:
            print("Clicked on Sexe")


    # [...]
    screen.blit(Sexe, [250,250])
    # [...]

如何解决此错误：“ pygame.Surface”对象不可下标

1 个答案: