我试图制作一个tkinter井字游戏GUI，但我一直试图将按钮的名称从空字符串更新为X或O，具体取决于轮到谁。每次我最终收到来自代码'NoneType' object is not subscriptable的{{1}}错误消息时，这是我的代码
button["text"] == "" import tkinter as tk
window = tk.Tk()
window.geometry("600x600")
window.title("Tic-Tac-Toe")
window.resizable(0, 0)
btn_click = True
def on_button_click(button):
global btn_click
if btn_click is True and button["text"] == "":
btn_click = False
button["text"] = "X"
elif btn_click is False and button["text"] == "":
btn_click = True
button["text"] = "O"
btn1 = tk.Button(window, text=" ", width=10, height=10, borderwidth=4, relief="groove", highlightcolor="red",
justify="center", padx=1, pady=1, command=lambda: on_button_click(btn1)).grid(row=1, column=1)
btn2 = tk.Button(window, text="12", width=10, height=10, borderwidth=4, relief="groove", highlightcolor="red",
justify="center", padx=1, pady=1, command=lambda: on_button_click(btn2)).grid(row=1, column=2)
btn3 = tk.Button(window, text="12", width=10, height=10, borderwidth=4, relief="groove", highlightcolor="red",
justify="center", padx=1, pady=1, command=lambda: on_button_click(btn3)).grid(row=1, column=3)
btn4 = tk.Button(window, text="12", width=10, height=10, borderwidth=4, relief="groove", highlightcolor="red",
justify="center", padx=1, pady=1, command=lambda: on_button_click(btn4)).grid(row=2, column=1)
btn5 = tk.Button(window, text="12", width=10, height=10, borderwidth=4, relief="groove", highlightcolor="red",
justify="center", padx=1, pady=1, command=lambda: on_button_click(btn5)).grid(row=2, column=2)
btn6 = tk.Button(window, text="12", width=10, height=10, borderwidth=4, relief="groove", highlightcolor="red",
justify="center", padx=1, pady=1, command=lambda: on_button_click(btn6)).grid(row=2, column=3)
btn7 = tk.Button(window, text="12", width=10, height=10, borderwidth=4, relief="groove", highlightcolor="red",
justify="center", padx=1, pady=1, command=lambda: on_button_click(btn7)).grid(row=3, column=1)
btn8 = tk.Button(window, text="12", width=10, height=10, borderwidth=4, relief="groove", highlightcolor="red",
justify="center", padx=1, pady=1, command=lambda: on_button_click(btn8)).grid(row=3, column=2)
btn9 = tk.Button(window, text="12", width=10, height=10, borderwidth=4, relief="groove", highlightcolor="red",
justify="center", padx=1, pady=1, command=lambda: on_button_click(btn9)).grid(row=3, column=3)
window.mainloop()
错误消息对我来说没有意义，因为我知道这只会将按钮文本更改为X或O。
button["text"] == ""似乎是一种替代方法，但是据我了解，这仅适用于标签和文本，不适用于按钮。我什至查看了许多教程和youtube视频，它们通常具有与我在上面的代码中实现的相同的方法，因此我不知道我在这里到底缺少什么。我今天刚开始学习tkinter，所以对我来说可能是一个简单的错误表示歉意。