在laravel / jquery应用程序中，如果我需要检查是否已登录用户，请在控制器中进行
$loggedUser = Auth::user();
if ( empty($loggedUser->id) ) {
return response()->json(['error_code'=> 1, 'message'=> "You must be logged!"],HTTP_RESPONSE_INTERNAL_SERVER_ERROR);
}
因为我不需要离开页面，而只限制了某些功能 我在上面使用bootstrapGrowl库显示错误消息。 现在使用laravel 7 / livewire 1.3 / turbolinks：5 / alpine @ v2，我搜索如何生成错误并 显示类似的错误消息，使用户留在页面上？
已更新：
让我用详细的示例进行说明： 在laravel / jquery应用中，我在JS代码中具有
var quiz_quality_radio= $('input[name=quiz_quality_radio]:checked').val()
var href = this_frontend_home_url + "/make-quiz-quality";
$.ajax( {
type: "POST",
dataType: "json",
url: href,
data: {"quiz_quality_id": quiz_quality_radio, "vote_id": this_vote_id, "_token": this_csrf_token},
success: function( response )
{
$('input[name=quiz_quality_radio]:checked').prop('checked', false);
frontendVote.showQuizQualityResults()
popupAlert("Thank you for rating ! Your rate was added!", 'success')
},
error: function( error )
{
$('input[name=quiz_quality_radio]:checked').prop('checked', false);
popupAlert(error.responseJSON.message, 'danger') // 'info', 'success'
}
});
和控制中的相对动作：
public function make_quiz_quality(Request $request)
{
$requestData = $request->all();
$quiz_quality_id = ! empty($requestData['quiz_quality_id']) ? $requestData['quiz_quality_id'] : '';
$vote_id = ! empty($requestData['vote_id']) ? $requestData['vote_id'] : '';
if ( ! Auth::check()) {
return response()->json(['message' => "To rate you must login to the system !"], HTTP_RESPONSE_BAD_REQUEST);
}
if (empty($quiz_quality_id)) {
return response()->json([
'message' => "To rate you must select quiz quality !",
'quiz_quality_id' => $quiz_quality_id
], HTTP_RESPONSE_OK);
}
$vote = Vote::find($vote_id);
if ($vote === null) {
return response()->json([ 'message' => "Vote Item # " . $vote_id . " not found !"],HTTP_RESPONSE_NOT_FOUND);
}
$loggedUser = Auth::user();
$found_count = QuizQualityResult
::getByVoteIdAndUserId($vote_id, $loggedUser->id)
->count();
if ($found_count > 0) {
return response()->json(['message' => "You have already rated '" . $vote->name . "' # vote !", 'vote_id' => $vote_id],
HTTP_RESPONSE_BAD_REQUEST);
}
$newVoteItemUsersResult = new QuizQualityResult();
try {
$newVoteItemUsersResult->quiz_quality_id = $quiz_quality_id;
$newVoteItemUsersResult->vote_id = $vote_id;
$newVoteItemUsersResult->user_id = $loggedUser->id;
DB::beginTransaction();
$newVoteItemUsersResult->save();
DB::commit();
} catch (Exception $e) {
DB::rollBack();
return response()->json(['message' => $e->getMessage(), 'voteCategory' => null], HTTP_RESPONSE_INTERNAL_SERVER_ERROR);
}
return response()->json(['message' => '', 'id' => $newVoteItemUsersResult->id], HTTP_RESPONSE_OK_RESOURCE_CREATED);
} // public function make_quiz_quality(Request $request)
并且在错误块中生成错误的情况下，我显示带有功能popupAlert的消息 （使用bootstrapGrowl实现），而无需离开页面。 那就是我想在livewire / turbolinks / alpine app中制作的。我该怎么办？
更新＃2：
那只是用户可以投票的物品清单：
<div class="table-responsive">
<table class="table text-primary">
@foreach($quizQualityOptions as $key=>$next_quiz_quality_option)
<tr>
<td>
<input class="" type="radio" name="quiz_quality_radio" id="quiz_quality_radio_{{ $next_quiz_quality_option }}" value="{{ $key }}">
<label class="col-form-label" for="quiz_quality_radio_{{ $next_quiz_quality_option }}">{{ $next_quiz_quality_option }}</label>
</td>
</tr>
@endforeach
</table>
</div>
<div class="row p-3">
<a class="btn btn-primary a_link" onclick="javascript:frontendVote.MakeQuizQuality()">Rate !</a>
</div>
有2个限制：
更新＃3：
我找到了使用axios的决定，例如：
<button type="submit" class="btn btn-primary btn-sm m-2 ml-4 mr-4 action_link" @click.prevent="submitNewTodo()">
Submit
</button>
submitNewTodo() {
console.log('submitNewTodo::')
let is_insert= 1
let current_toto_id= 1
axios({
method: (is_insert ? 'post' : 'patch'),
url: '/api/todos' + (!is_insert ? "/" + current_toto_id : ''),
data: {
text : this.new_todo_text,
priority : this.new_todo_priority
},
}).then((response) => {
this.new_todo_text= ''
this.new_todo_priority= ''
this.loadTodosRows()
popupAlert( 'Todo ' + (is_insert ? 'added' : 'updated') + ' successfully !', 'success' )
}).catch((error) => {
var validationErrors= convertObjectToArray(error.response.data.errors.text)
this.validation_errors_text= ''
validationErrors.map((next_error, index) => {
if(next_error && typeof next_error[1] != "undefined" ) {
this.validation_errors_text += '<li>'+next_error[1]+'</li>'
}
})
popupErrorMessage(error.response.data.message)
});
},
有了它，我可以根据需要显示成功和失败的信息，但是我看到了很大的缺点 因为我使用livewire，如果可能的话，我想在这里使用livewire ... 希望我清楚地解释了我想要的...
谢谢！
答案 0 :(得分：1)
使用Alpine.js和axios，您可以执行以下操作，请注意，我不确定是否将定义this_frontend_home_url，this_vote_id和this_csrf_token。
<div x-data="quiz()">
<div>
<div class="table-responsive">
<table class="table text-primary">
@foreach($quizQualityOptions as $key=>$next_quiz_quality_option)
<tr>
<td>
<input x-model="selected_quiz" class="" type="radio" name="quiz_quality_radio"
id="quiz_quality_radio_{{ $next_quiz_quality_option }}" value="{{ $key }}">
<label class="col-form-label"
for="quiz_quality_radio_{{ $next_quiz_quality_option }}">{{ $next_quiz_quality_option }}</label>
</td>
</tr>
@endforeach
</table>
</div>
<div class="row p-3">
<a class="btn btn-primary a_link" @click="submitQuizQuality()">Rate !</a>
</div>
</div>
</div>
<script>
function quiz() {
return {
selected_quiz: null,
submitQuizQuality() {
const url = this_frontend_home_url + "/make-quiz-quality";
axios.post(url, {
quiz_quality_id: this.selected_quiz,
vote_id: this_vote_id, // no idea where this is coming from,
_token: this_csrf_token // no idea where this is coming from
}).then(() => {
// reset "checked" state
this.selected_quiz = null;
frontendVote.showQuizQualityResults();
popupAlert("Thank you for rating ! Your rate was added!", 'success');
}).catch(error => {
// reset "checked" state
this.selected_quiz = null;
if (error && error.response) {
popupAlert(error.response.message, 'danger')
}
});
}
}
}
</script>