Question

我有一个这样的对象数组：

const customers = [
    {
        customer_name: 'Negan Lucille', 
        customer_age: 45, 
        customer_weapon: 'Bat',
        customer_email: 'negan@sanctuary.com',
        customer_city: 'Washington' 
    },
    {
        customer_name: 'Daryl Dixon', 
        customer_age: 41, 
        customer_weapon: 'Crossbow',
        customer_email: 'daryl.dixon@kickass.com',
        customer_city: 'Atlanta' 
    },
    {
        customer_name: 'Rick Grimes', 
        customer_age: 45, 
        customer_weapon: 'Magnum 357',
        customer_email: 'rick@alexandria.com',
        customer_city: 'King County' 
    },
];

，我想将customer_name分为名字和姓氏，因此名字应保留在customer_name中，姓氏应放在新创建的属性customer_last_name中。我也有newKeys数组，可用来替换customers对象中的当前键，如下所示：

const newKeys = [
   'firstname',
   'lastname',
   'age',
   'weapon',
   'email',
   'city'
]

let newCustomers = customers.map(obj => 
    Object.values(obj).reduce((acc, cur, i) => { 
       acc[newKeys[i]] = cur; 
       return acc; }, {}));

新数组应如下所示：

customers = [
  {
    firstname: 'Negan',
    lastname: 'Lucille', 
    age: 45, 
    weapon: 'Bat',
    email: 'negan@sanctuary.com',
    city: 'Washington' 
  },
  {
    firstname: 'Daryl', 
    lastname: 'Dixon',
    age: 41, 
    weapon: 'Crossbow',
    email: 'daryl.dixon@kickass.com',
    city: 'Atlanta' 
  },
  {
    firstname: 'Rick', 
    lastname: 'Grimes',
    age: 45, 
    weapon: 'Magnum 357',
    email: 'rick@alexandria.com',
    city: 'King County' 
  },
]

做到这一点的最佳方法是什么？一个例子将不胜感激！

Answer 1

假设名字中没有空格，则可以使用string.split

然后您可以使用Array.prototype.shift来获取第一个元素，而其余join一起放回去。

在我的示例中，我将名字更改为具有2个单词的姓氏作为演示

const customers = [
    {
        customer_name: 'Negan De Lucille', 
        customer_age: 45, 
        customer_weapon: 'Bat',
        customer_email: 'negan@sanctuary.com',
        customer_city: 'Washington' 
    },
    {
        customer_name: 'Daryl Dixon', 
        customer_age: 41, 
        customer_weapon: 'Crossbow',
        customer_email: 'daryl.dixon@kickass.com',
        customer_city: 'Atlanta' 
    },
    {
        customer_name: 'Rick Grimes', 
        customer_age: 45, 
        customer_weapon: 'Magnum 357',
        customer_email: 'rick@alexandria.com',
        customer_city: 'King County' 
    },
];

for (const i in customers) {
  const names = customers[i].customer_name.split(" ");
  const newCustomer = {
    age: customers[i].customer_age
    //add in the other properties
  }
  newCustomer.firstname = names.shift();
  newCustomer.lastname = names.join(" ");
  customers[i] = newCustomer;
};

console.log(customers);

Answer 2

使用split()分解名称，添加新属性，然后删除旧属性。

const customers = [
    {
        customer_name: 'Negan Lucille', 
        customer_age: 45, 
        customer_weapon: 'Bat',
        customer_email: 'negan@sanctuary.com',
        customer_city: 'Washington' 
    },
    {
        customer_name: 'Daryl Dixon', 
        customer_age: 41, 
        customer_weapon: 'Crossbow',
        customer_email: 'daryl.dixon@kickass.com',
        customer_city: 'Atlanta' 
    },
    {
        customer_name: 'Rick Grimes', 
        customer_age: 45, 
        customer_weapon: 'Magnum 357',
        customer_email: 'rick@alexandria.com',
        customer_city: 'King County' 
    },
];

const refactored = customers.map(customer=>{
  var [firstname, lastname] = customer.customer_name.split(/\s/);
  return {
    firstname, lastname,
    age: customer.customer_age,
    weapon: customer.customer_weapon,
    email: customer.customer_email,
    city: customer.customer_city
  }
});

console.log(refactored);

Answer 3

const customers = [
    {
        customer_name: 'Negan Lucille', 
        customer_age: 45, 
        customer_weapon: 'Bat',
        customer_email: 'negan@sanctuary.com',
        customer_city: 'Washington' 
    },
    {
        customer_name: 'Daryl Dixon', 
        customer_age: 41, 
        customer_weapon: 'Crossbow',
        customer_email: 'daryl.dixon@kickass.com',
        customer_city: 'Atlanta' 
    },
    {
        customer_name: 'Rick Grimes', 
        customer_age: 45, 
        customer_weapon: 'Magnum 357',
        customer_email: 'rick@alexandria.com',
        customer_city: 'King County' 
    },
];

for(let i=0;i<customers.length;i++){
   let name = customers[i].customer_name.split(' ')  
   customers[i].customer_name=name[0]
   customers[i].customer_last=name[1]  
   
   }
   
   console.log(customers)

如何仅获取对象值的第一个单词

3 个答案: