Question

所以这就是我正在使用的所有代码。我只是练习用askopenfilename（）函数，那是我遇到这个问题的时候

from tkinter import *

from PIL import ImageTk,Image

import tkinter.messagebox as tmsg

import tkinter.filedialog as fd



def open_1():

    name = fd.askopenfilename(initialdir="/",title="Select Files",filetypes=(("png File","*.png"),("All 
    Files","*.*")))
    label_1 = Label(root,text = f"{name}",borderwidth = 2,relief="groove")
    label_1.grid()
    my_img = Image.open(f"{name}")
    my_img_1 = ImageTk.PhotoImage(my_img)
    label_2 = Label(root, image=my_img_1, borderwidth=2, relief="groove")
    label_2.grid(row=1,column=0)
    print(name)



root = Tk()
root.geometry("700x500")
root.title("File_Dialouge Test")

img = ImageTk.PhotoImage(Image.open("22.jpg"))
root.iconphoto(False,img)


def test():

    print("It Works You  Idoit")


def save():

    fd.asksaveasfile()


def save_as():
    pass


def exit():

    pass

file = Menu(root)
file_1 = Menu(file,tearoff=False)
file_1.add_command(label="Open", command = open_1)
file_1.add_command(label="Save",command = save)
file_1.add_command(label="Save As",command = save_as)
file_1.add_command(label="Exit",command = exit)
root.config(menu=file)
file.add_cascade(label="FILE", menu = file_1)
root.mainloop()

最终输出在图像中： This is the final output I'm getting, only the image borders are visible instead of actual image

我在标签内部显示图像时遇到问题，使用askopenfilename（）作为路径

0 个答案: