如何将这两个脚本合并为一个函数,
<script>//<![CDATA[
function LMcheckCheckbox(){
document.querySelectorAll(".checkbox").forEach(function(e) {
"darkmode"===localStorage.getItem("mode")?e.checked=!0:e.checked=!1
})
}
function darkMode(){
localStorage.setItem("mode","darkmode"===localStorage.getItem("mode")?"light":"darkmode"),
"darkmode"===localStorage.getItem("mode")?document.querySelector("body").classList.add("darkmode"):document.querySelector("body").classList.remove("darkmode"),
LMcheckCheckbox()
}
function darkModeHide(){
document.querySelectorAll(".darkmode-switch").forEach(function(e){
e.parentNode.removeChild(e)
})
}
LMcheckCheckbox(),
"undefined"==typeof AzidBloggerSetting
&&(AzidBloggerSetting={tombolDarkmode:!0}),
0==AzidBloggerSetting.tombolDarkmode&&darkModeHide();
//]]>
</script>
和此处用于更改元主题颜色的脚本
$("meta[name='theme-color']").attr('content', '#333333');
如何将第二个脚本插入第一个脚本?我想在第一个脚本处于活动状态时更改meta主题颜色。
答案 0 :(得分:0)
您需要找到激活暗模式的位置,然后将代码放入其中。(对代码进行最小化以首先查看发生了什么事情
我建议您在进入代码之前对javascript有基本的了解!
据我了解,这就是您想要做的:
function LMcheckCheckbox() {
document.querySelectorAll(".checkbox").forEach(function(e) {
"darkmode" === localStorage.getItem("mode") ? e.checked = !0 : e.checked = !1
})
}
function darkMode() {
// this is seemingly where the dark mode is being applyed so :
$("meta[name='theme-color']").attr('content', '#333333');
localStorage.setItem("mode", "darkmode" === localStorage.getItem("mode") ? "light" : "darkmode"), "darkmode" === localStorage.getItem("mode") ? document.querySelector("body").classList.add("darkmode") : document.querySelector("body").classList.remove("darkmode"), LMcheckCheckbox()
}
function darkModeHide() {
document.querySelectorAll(".darkmode-switch").forEach(function(e) {
e.parentNode.removeChild(e)
})
}
LMcheckCheckbox(), "undefined" == typeof AzidBloggerSetting && (AzidBloggerSetting = {
tombolDarkmode: !0
}), 0 == AzidBloggerSetting.tombolDarkmode && darkModeHide();