Question

我正在尝试写一个拼写检查器，告诉您句子中哪些单词的拼写错误。它应该从输入中读取特定的句子，并查看该句子中的单词是否属于给定列表。如果它们不是一部分，则应打印出不合适的单词。如果一切正确，则应打印“确定”。但是，我无法让它仅打印不正确的单词，而不能遍历整个列表并多次打印OK。

到目前为止，这是我的代码：

dictionary = ['all', 'an', 'and', 'as', 'closely', 'correct', 'equivocal',
              'examine', 'indication', 'is', 'means', 'minutely', 'or', 'scrutinize',
              'sign', 'the', 'to', 'uncertain']

sentence = input()
sentence = sentence.split()

for word in sentence:
    if word not in dictionary:
        print(word)
    elif word in dictionary:
        print("OK")
        break

Answer 1

这是因为当您看到错误的单词时使用break。这意味着它将停止循环，并因此找不到其他不正确的单词。

您想要的代码如下：

dictionary = ['all', 'an', 'and', 'as', 'closely', 'correct', 'equivocal',
              'examine', 'indication', 'is', 'means', 'minutely', 'or', 'scrutinize',
              'sign', 'the', 'to', 'uncertain']

sentence = input()
sentence = sentence.split()

found_incorrect_word = False
for word in sentence:
    if word not in dictionary:
        print(word)
        found_incorrect_word = True  # no break here
        
if not found_incorrect_word:
    print("OK")

Answer 2

您的问题是，您在输入正确单词的那一刻就开始努力。试试这个：

dictionary = ['all', 'an', 'and', 'as', 'closely', 'correct', 'equivocal',
              'examine', 'indication', 'is', 'means', 'minutely', 'or', 'scrutinize',
              'sign', 'the', 'to', 'uncertain']

sentence = input()
sentence = sentence.split()

incorrect = False
for word in sentence:
    if word not in dictionary:
        print(word)
        incorrect = True


if not incorrect:
    print("OK")

Answer 3

使用列表理解来检测错误的单词

dictionary = ['all', 'an', 'and', 'as', 'closely', 'correct', 'equivocal',
              'examine', 'indication', 'is', 'means', 'minutely', 'or', 'scrutinize',
              'sign', 'the', 'to', 'uncertain']

sentence = input('Enter sentence: ')
sentence = sentence.split()
incorrect_words = [word for word in sentence if not word in dictionary]

if incorrect_words:
    print(*incorrect_words, sep='\n')
else:
    print('All words OK')

或更简洁

incorrect_words = [word for word in input('Enter sentence: ').split() if not word in dictionary]

if incorrect_words:
    print(*incorrect_words, sep='\n')
else:
    print('All words OK')

我在处理清单时遇到麻烦

3 个答案: