disc@puff:~/php$ ls
a.php data include
disc@puff:~/php$ tree
.
├── a.php
├── data
│ └── d.php
└── include
├── b.php
└── c.php
2 directories, 4 files
disc@puff:~/php$ cat a.php
a.php is including include/b.php ...
<?php include "include/b.php" ?>
disc@puff:~/php$ cat include/b.php
b.php is including c.php and ../data/d.php ...
<?php include "c.php" ?>
<?php include "../data/d.php" ?>
disc@puff:~/php$ cat include/c.php
c.php
disc@puff:~/php$ cat data/d.php
d.php
disc@puff:~/php$ php a.php
a.php is including include/b.php ...
b.php is including c.php and ../data/d.php ...
c.php
PHP Warning: include(../data/d.php): failed to open stream: No
such file or directory in /home/disc/php/include/b.php on line 3
PHP Warning: include(): Failed opening '../data/d.php' for
inclusion (include_path='.:/usr/share/php:/usr/share/pear') in /home/
disc/php/include/b.php on line 3
disc@puff:~/php$
为什么include "c.php"
成功但include "../data/d.php"
失败?
http://www.php.net/manual/en/function.include.php提到:“如果有路径 定义 - 是否绝对(以驱动器号或\开头 Windows,或/在Unix / Linux系统上)或相对于当前 目录(以。或..开头) - include_path将被忽略 共。例如,如果文件名以../开头,那么解析器 将查看父目录以查找所请求的文件。 “
父目录是什么?
答案 0 :(得分:2)
路径始终相对于被调用的脚本。在你的例子中加载c.php是因为“。” (当前目录)始终位于include_path中。
要解决此问题,您可以使用dirname(__FILE__)
始终知道文件本身的目录。 (您编写文件的文件)
或者您可以使用dirname($_SERVER['SCRIPT_FILENAME'])
来获取校准脚本的目录。
答案 1 :(得分:1)
当您从a.php
开始时,您应该在a.php
中定义包含目录:
define('MY_INCLUDES', dirname(__FILE__) . '/include/');
define('MY_DATA', dirname(__FILE__) . '/data/');
然后包含具有绝对路径的文件:
include(MY_INCLUDES . 'b.php');
include(MY_DATA . 'c.php');