Question

我正在尝试为一件快速的事情创建一个交互式故事代码，而我的布尔值似乎并没有在代码中从true变为false。在这里：

age = input ("Type in your age")
print("You're bored during quarantine and decide to go visit a haunted house alone. You visit the house, open the door, and walk in.")
print("You are in front of a creepy door in a hallway.")
print("What do you want to do?")
action = input ("Type: in, left, or right. Then click OK or press enter")
survive = False

def survival():
  if age%2 == 0:
    survive = False
  else:
    survive = True
    
survival()

if action == "in":
  print("You choose to go in.")
  print("The room is pitch black")
  if survive == False:
    print("A monster pops out of the corner and eats you!")
  else:
    print("You turn the light on and realize that this is just an old bathroom. Gross.")
if action == "left":
  print("You choose to turn left.")
  print("A ghost appears at the end of the hall.")
  if survive == False:
    print("The ghost chases you down and haunts your soul forever!")
  else:
    print("Your eyes mistook you, it was a spiderweb.")
if action == "right":
  print("You choose to turn right")
  print("A greenish light is visible in the distance")
  if survive == False:
    print("The light gets brighter and brighter, and you realize it was the headlamp of a ghost coal miner!")
  else:
    print("You go to check out the light, turns out it's some old christmas lighting still plugged in.")
    
if survive == False:
  print("May your soul rest eternally as you join the other ghosts at the haunted house.")
else:
  print("You survived your stay at the haunted house and apparently it's just a house.")

您可以看到我正在尝试获取该人的年龄，如果该值均匀地除以2，则将生存时间设置为false。但是，无论您进入多大的年龄，无论是偶数还是奇数，都仍然可以生存= false。有什么想法可能有问题吗？

Answer 1

函数中的变量是局部变量，age在函数外部。因此，您需要在函数中使用global关键字为


    def survival():
        global age
        global survive
        if age%2 == 0:
            survive = False
        else:
            survive = True

第二，您将年龄输入作为字符串，当您使用运算符时，这将为您提供Type error。您需要将其转换为整数
age=int(age)或age=int(input())。

最后，我建议您像@ juanpa.arrivillaga所说的那样在函数中传递值：


    def survival():
        age=int(input())
        survive=False

或


    def survival(age,survive=False):

Answer 2

更改这段代码：

survive = False   # Useless statement -- you replace the value on the following main-program line

def survival():
  if age%2 == 0:
    survive = False    # No need to set a variable; just return the Boolean value
  else:
    survive = True
    
survival()    # Make this line save a return value

对此：

def survival():
    return age%2 == 1

survive = survival()

此外，我认为您需要更多关于布尔的练习。从不将变量与布尔常量进行比较：请改用逻辑运算符。你在哪里

if survive == False:

替换为

if not survive:

更好的是，逆转生存检查的逻辑：

def kill_me():
    return age%2 == 0

sudden_death = kill_me()

...

if sudden_death:
    print("Cthulhu rises through the floor; his presence destroys your very soul.")

Answer 3

解决此问题的一种方法如下，希望对您有所帮助

age = int(input ("Type in your age\n"))
print("You're bored during quarantine and decide to go visit a haunted house alone. You 
visit the house, open the door, and walk in.")
print("You are in front of a creepy door in a hallway.")
print("What do you want to do?")
action = input ("Type: in, left, or right. Then click OK or press enter\n")

def survival(age=age):
  if age%2 == 0:
    return False
  else:
    return True

if action == "in":
  print("You choose to go in.") 
    if survival() == False:
      print("A monster pops out of the corner and eats you!")
    else:
      print("You turn the light on and realize that this is just an old bathroom. Gross.")
if action == "left":
  print("You choose to turn left.")
  print("A ghost appears at the end of the hall.")
  if survival() == False:
    print("The ghost chases you down and haunts your soul forever!")
  else:
    print("Your eyes mistook you, it was a spiderweb.")
if action == "right":
  print("You choose to turn right")
  print("A greenish light is visible in the distance")
  if survival() == False:
    print("The light gets brighter and brighter, and you realize it was the headlamp of a ghost coal miner!")
  else:
    print("You go to check out the light, turns out it's some old christmas lighting still plugged in.")

if survival() == False:
  print("May your soul rest eternally as you join the other ghosts at the haunted house.")
else:
  print("You survived your stay at the haunted house and apparently it's just a house.")

Answer 4

只需在代码中修改以下内容即可。

您输入年龄作为字符串。在Python中， input（）返回字符串值。您应该将输入值转换为整数。为此，您可以使用 int（）方法。

age = int（输入（“键入您的年龄”））

或

age = input ("Type in your age")
age = int(age)

您使用年龄并在生存功能中生存。但是两者都在生存功能之外定义。因此，请使用 global 关键字在生存功能中使用它们。因此，应按以下方式更正代码，

def survival():
  global survive
  global age
  if age%2 == 0:
    survive = False
  else:
    survive = True

函数不将布尔值从true更改为false

4 个答案: