Question

我正在构建一个Spring应用程序，该应用程序使用Stripe进行基于订阅的付款。我在创建订阅时遇到问题，我得到的确切错误是：org.hibernate.AssertionFailure: non-transient entity has a null id: com.randomprogramming.projectstrics.entity.Account，但这没有任何意义，因为当我打开数据库（PostgreSQL）时，我可以看到该帐户有一个ID。但是，当我检查Subscription上的Account字段时，该字段为空。以下是应该创建Subscription并将其保存在我的数据库中的代码：

public Subscription createSubscription(CreateSubscriptionBody createSubscriptionBody, Principal principal) throws Exception {
        logger.info("Started creating a new subscription...");
        // probably not necessary to check both the principal and account but just to be safe
        if (principal == null) throw new Exception("Principal not defined, check if you are logged in.");
        Account customerAccount = accountService.findByUsername(principal.getName());
        if (customerAccount == null) throw new UsernameNotFoundException("Error when searching for user.");

        logger.info("Creating the Customer and PaymentMethod...");
        // Create a Customer object from the passed in Customer ID
        Customer customer = Customer.retrieve(createSubscriptionBody.getCustomerId());
        // Create a PaymentMethod from the passed in Payment Method ID
        PaymentMethod pm = PaymentMethod.retrieve(createSubscriptionBody.getPaymentMethodId());
        // Attach the Customer ID to the Payment Method
        pm.attach(PaymentMethodAttachParams.builder().setCustomer(customer.getId()).build());

        logger.info("Creating CustomerUpdateParams and updating Customer...");
        // I don't even know what this does
        CustomerUpdateParams customerUpdateParams = CustomerUpdateParams
                .builder()
                .setInvoiceSettings(
                        CustomerUpdateParams
                                .InvoiceSettings.builder()
                                .setDefaultPaymentMethod(createSubscriptionBody.getPaymentMethodId())
                                .build()
                )
                .build();
        // and we update the customer with whatever the fuck we did above
        customer.update(customerUpdateParams);

        logger.info("Creating the Subscription params...");
        // Create the subscription params
        SubscriptionCreateParams subCreateParams = SubscriptionCreateParams
                .builder()
                .addItem(
                        SubscriptionCreateParams
                                .Item.builder()
                                .setPrice(PRICE_ID)
                                .build()
                )
                .setCustomer(customer.getId())
                .addAllExpand(Collections.singletonList("latest_invoice.payment_intent"))
                .build();

        logger.info("Creating the subscription...");
        // Create the subscription
        // I'm pretty sure that Subscription.create is async, so be careful with this
        Subscription subscription = Subscription.create(subCreateParams);

        // Save the subscription that was returned into our database
        StripeSubscription stripeSubscription = new StripeSubscription(subscription.getId(),
                subscription.getCurrentPeriodEnd(),
                subscription.getCustomer(),
                // Since we're only going to be charging for one thing, we can use 0 index here
                subscription.getItems().getData().get(0).getPrice().getId(), customerAccount);
        save(stripeSubscription);

        // Save the subscription to the account and save the account into the database
        customerAccount.setSubscription(stripeSubscription);
        accountService.save(customerAccount);

        logger.info("Finished creating the subscription.");
        return subscription;
    }

在使用调试器运行该程序几次后，我注意到该错误发生在行save(stripeSubscription);上。当使用调试器检查值时，所有内容都有一个ID，对我来说一切都很好。

这是保存方法：

    public void save(StripeSubscription stripeSubscription) {
        stripeSubscriptionRepository.save(stripeSubscription);
        logger.info("Saved StripeSubscription in the database.");
    }

这是我的StripeSubscription实体：

@Entity(name = "stripe_subscription")
@AllArgsConstructor
@NoArgsConstructor
@Getter
@Setter
public class StripeSubscription {
    @Id
    private String id;
    private Long currentPeriodEnd;
    private String customerId;
    private String priceId;

    @JsonIgnore
    @OneToOne(mappedBy = "subscription")
    private Account account;
}

要注意的另一件事是实际上已创建了订阅，可以从我的Stripe仪表板检查该订阅。我在做什么错了？

Answer 1

嗯，我尝试在StripeSubscription中创建一个新的ID字段，并将订阅ID保存在另一个字段中，这似乎已经解决了问题。

在春季创建条纹订阅的问题

1 个答案: