我创建了一个警报对话框,用户可以在其中更新其个人资料详细信息。在带有图像容器的容器中,有一个图标按钮小部件。我要的是当用户单击图标按钮时,将显示带有添加/删除图像选项的弹出菜单。这是我的警报对话框代码:
Traceback (most recent call last):
File "face.py", line 1, in <module>
import face_recognition
File "/home/user/.local/lib/python3.7/site-packages/face_recognition/__init__.py", line 7, in <module>
from .api import load_image_file, face_locations, batch_face_locations, face_landmarks, face_encodings, compare_faces, face_distance
File "/home/user/.local/lib/python3.7/site-packages/face_recognition/api.py", line 4, in <module>
import dlib
ImportError: Python version mismatch: module was compiled for version 3.8, while the interpreter is running version 3.7.
我试图为此使用showMenu。但是由于该职位必须进行硬编码,所以我不是要使用它。 我尝试过的:
showDialog<void>(
builder: (BuildContext context) {
return AlertDialog(
title: Text('Update details'),
shape: RoundedRectangleBorder(borderRadius: BorderRadius.all(Radius.circular(8.0))),
content: StatefulBuilder(
builder: (context, setState) { return Container(
width: 400,
child: Form(
key: _formKey,
child: Column(
mainAxisAlignment: MainAxisAlignment.spaceAround,
children: <Widget>[
Stack(
alignment: Alignment.center,
children: [
Container(
width: 100.0,
height: 100.0,
decoration: new BoxDecoration(
shape: BoxShape.circle,
image: new DecorationImage(
fit: BoxFit.cover,
colorFilter: new ColorFilter.mode(Colors.black.withOpacity(0.2), BlendMode.darken),
image: data != null ? MemoryImage(data) : AssetImage("web/icons/contactsDefaultImage.png")
)
)
),
IconButton(icon: Icon(Icons.edit), onPressed: () async {
//display option here
_showPopupMenu();
})
]),
Container(
child: TextFormField(
decoration: InputDecoration(
labelText: 'name'
),
),
),
TextFormField(
decoration: InputDecoration(
labelText: 'email'
),
),
],
),
),
);},
),
actions: <Widget>[
FlatButton(
child: Text('Cancel'),
onPressed: () {
Navigator.of(context).pop();
},
),
FlatButton(child: Text('Save'),
onPressed: () {
// save
},
)
],
);
},
);
}
现在,我想知道的是如何在点击图标按钮的地方显示它(而无需对值进行硬编码)。还有另一种方法可以做到这一点,即不使用showMenu。
答案 0 :(得分:2)
您可以编写这样的方法,然后在图标按钮的onPressed
_showPopupMenu(){
showMenu<String>(
context: context,
position: RelativeRect.fromLTRB(25.0, 25.0, 0.0, 0.0), //position where you want to show the menu on screen
items: [
PopupMenuItem<String>(
child: const Text('menu option 1'), value: '1'),
PopupMenuItem<String>(
child: const Text('menu option 2'), value: '2'),
PopupMenuItem<String>(
child: const Text('menu option 3'), value: '3'),
],
elevation: 8.0,
)
.then<void>((String itemSelected) {
if (itemSelected == null) return;
if(itemSelected == "1"){
//code here
}else if(itemSelected == "2"){
//code here
}else{
//code here
}
});
}
答案 1 :(得分:1)
您要查找的是showdialog和alertdialog。
Void<String> testdialog(BuildContext context) {
return showDialog(
barrierDismissible: false,
context: context,
builder: (context) {
return StatefulBuilder(builder: (context, setState) {
return AlertDialog(
title: ....
答案 2 :(得分:1)