Question

给出日期，返回该日期所在季度之前的季度最后一天的日期。例如

2020-04-25 => 2020-03-31
2020-06-25 => 2020-03-31
2020-09-25 => 2020-06-30
2020-10-25 => 2020-09-30

如果给定的日期在第一季度，则年份减去1

2020-03-25 => 2019-12-31

Answer 1

      <div class="email-div">
        <i class="fas fa-user-shield"></i>
        <input type="email" name="email" id="em-id" placeholder="Email" min="3" max="15" 
        spellcheck="false" required="true">
      </div>
     <div class="pass-div">
       <i class="fas fa-lock"></i>
       <input type="password" name="password" id="pass" placeholder="Password" min="8" max="32" 
       spellcheck="false" required="true">
     </div>
     <div class="btn-div">
       <button class="btn" id="login-btn" v-on:click="login">LOGIN</button>
     </div>




    login: function() {
        let email = document.getElementById('em-id').value
        let password = document.getElementById('pass').value
        if(email && password) {
          console.log('email => ', + email)       //gives output Nan 
          console.log('password => ' + password)
       }
    }

这至少需要Rakudo 2020.05。

Answer 2

sub MAIN(Str $day) {
    my Date $d       = Date.new($day);
    my Int  $year    = $d.year;
    my Int  $month   = $d.month;
    my Int  $quarter = ($month/3).ceiling; # the quarter that this date falls

    my @last-days = ('12-31', '03-31', '06-30', '09-30');

    # if the given date is in the first quarter, then `$year` minus 1
    $year-=1 if $quarter == 1; 

    say sprintf('%s-%s', $year, @last-days[$quarter-1]);
 }

将上述代码另存为quarter.raku，输出为：

$ raku quarter.raku 2020-03-25
2019-12-31
 
$ raku quarter.p6 2020-04-25
2020-03-31
 
$ raku quarter.p6 2020-06-25
2020-03-31
 
$ raku quarter.p6 2020-07-25
2020-06-30

$ raku quarter.p6 2020-08-25
2020-06-30
 
$ raku quarter.p6 2020-09-25
2020-06-30
 
$ raku quarter.p6 2020-10-25
2020-09-30

获取该日期所在季度之前的季度最后一天的日期

2 个答案: