Question

我想依次遍历三个列表中的每一个，在每次迭代中从每个列表中选择一个元素。

subjects=["Americans","Indians"]
verbs=["plays","watch"]
objects=["Baseball","cricket"]
for i,j,k in zip(subjects,verbs,objects):
    print(i,j,k)

上面的代码给出的输出如下：

Americans plays Baseball

Indians watch cricket

但预期的输出是：

Americans play Baseball.

Americans play Cricket.

Americans watch Baseball.

Americans watch Cricket.

Indians play Baseball.

Indians play Cricket.

Indians watch Baseball.

Indians watch Cricket.

Answer 1

使用itertools.product获取所有可能的组合，然后打印它们

>>> subjects=["Americans","Indians"]
>>> verbs=["plays","watch"]
>>> objects=["Baseball","cricket"]
>>> 
>>> from itertools import product
>>> for x in product(subjects,verbs,objects):
...     print('{} {} {}'.format(*x))
... 
Americans plays Baseball
Americans plays cricket
Americans watch Baseball
Americans watch cricket
Indians plays Baseball
Indians plays cricket
Indians watch Baseball
Indians watch cricket

Answer 2

您可以这样迭代解决方案：

subjects=["Americans","Indians"] 
verbs=["plays","watch"] 
objects=["Baseball","cricket"]


for s in subjects:
    for v in verbs:
        for o in objects:
            print(s,v,o+".")

Answer 3

itertools.product是最好的解决方案，但是如果您不想导入模块，那么下一个最有效的解决方案是生成器表达式。

subjects = ["Americans", "Indians"]
verbs = ["play", "watch"]
objects = ["Baseball", "Cricket"]

# paragraph = "\n".join(f"{s} {v} {o}." for s in subjects for v in verbs for o in objects)  # Alternative single-liner
for sentence in (f"{s} {v} {o}." for s in subjects for v in verbs for o in objects):
    print(sentence)

输出

Americans play Baseball.
Americans play Cricket.
Americans watch Baseball.
Americans watch Cricket.
Indians play Baseball.
Indians play Cricket.
Indians watch Baseball.
Indians watch Cricket.

多次迭代三个列表，每次迭代从列表中依次选择一个元素

3 个答案: